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DENIUS [597]
3 years ago
15

Marcelo can select from 2 types of oranges and 3 types of peaches. If he randomly selects 1 orange and 1 peach, how many possibl

e choices does he have? ___________ possible choices
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0
6

2x3=6

oranges-
peaches-

possible combination:
1-

2-

3-

4-

5-

6-
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Let D = {x| x is a student} be the domain, and let ƒ(x) = “date of birth” be the possible function. Determine if the relation is
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A relation is a function if the value in its Domain does not occur more than once. This means each domain value is paired with exactly one value of range.

In the given scenario, the domain is the students (e.g name of a student) and the function returns the date of birth of the student. A student can have only one date of birth. So it is not possible that a value in Domain(i.e. a student) is paired with more than one date of births. 

Therefore, we can conclude that the given relation describes a function. 
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The American Community Survey showed that residents of New York City have the longest travel times to get to work compared to re
LiRa [457]

Answer:

The probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the travel times to get to work.

The expected travel time is, <em>μ</em> = 38.3 minutes.

The distribution of random variable <em>X</em> can be defined as the distribution of time interval between which a person reaches their work place at a constant average rate.

This implies that <em>X</em> follows an Exponential distribution with parameter, \lambda=\frac{1}{\mu}=\frac{1}{38.3}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda e^{-\lambda x};\ x\geq 0

Compute the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work as follows:

P(17.24\leq X\leq 42.13)=\int\limits^{42.13}_{17.24}{\frac{1}{38.3} e^{-x/38.3}}}\, dx

                                   =\frac{1}{38.3}\times \int\limits^{42.13}_{17.24}{ e^{-x/38.3}}}\, dx

                                   =\frac{1}{38.3}\times| \frac{e^{-x/38.3}}{-1/38.3}}|^{42.13}_{17.24}\\

                                   =-e^{42.13/38.3}+e^{17.34/38.3}\\=-0.3329+0.6375\\=0.3046

Thus, the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

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