Answer:
The integers are 4 and 7 or -2 and 1.
Step-by-step explanation:
You can make a system of equations with the description of the two integers.
1. x = y + 3
2. 2x + 2 = y^2
The simplest and the fastest way to solve this system in this case is substitution. You can substitute x for y + 3 in the second equation.
1. x = y + 3
2. 2(y + 3) + 2 = y^2
Now simplify and solve the second one. For convenience, I will just disregard the first equation for now.
2y + 6 + 2 = y^2
y^2 - 2y - 8 = 0
You can factor this equation to solve for y.
(y - 4) (y + 2) = 0
y = 4, y = -2
Now we can substitute the value of y for x in the first equation.
x = 7, x = 1
Answer:
x=ln(41)/ln(243)
Step-by-step explanation:
20(3)^5x=820
3^5x=820/20
3^5x=41
5x=ln(41)/ln(3)
x=(1/5)[ln(41)/ln(3)]
x=ln(41)/ln(3^5)
x=ln(41)/ln(243)
Step-by-step explanation:
1. x: (-12, -13) y: (12, 13)
2. x: (4 ,9) y: (-4, -9)
3. x: (-10, 8) y: (10, -8)
Answer:
∡S corresponds to ∡X
∡TXY = ∡RST
∡XTY = ∡SRT
∡XYT = ∡STR
Step-by-step explanation: