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Lyrx [107]
2 years ago
5

what is an art and a science that deals with the collection,organization,creative presentation and analysis of data? A.physics B

.statistics C. biology D.sampling​
Mathematics
1 answer:
DENIUS [597]2 years ago
7 0

Answer:

The answer is B. Statistics

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A standard deck of cards contains 52 cards. One card is selected from the deck.​(a)Compute the probability of randomly selecting
Aneli [31]

a. There are four 5s that can be drawn, and \binom43=4 ways of drawing any three of them. There are \binom{52}3=22,100 ways of drawing any three cards from the deck. So the probability of drawing three 5s is

\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of \frac8{52}=\frac2{13}\approx0.15 of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability \frac{12}{52}=\frac3{13}\approx0.23 of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of \frac{16}{52}=\frac4{13}\approx0.31.

- - -

Note: \binom nk is the binomial coefficient,

\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k

6 0
3 years ago
Helppppppppppppppp !!!!!!
algol [13]

Answer:

\sqrt{2^{5}  } is correct

Step-by-step explanation:

6 0
3 years ago
How do you add add fraction with a different denominator?
kenny6666 [7]

Find the LCM (least common multiple) of the denominators, and use that as the denominator for the two fractions.

Ex.

\frac{3}{4} +\frac{2}{3}

LCM (3, 4) is 12

\frac{9}{12} +\frac{8}{12}

=\frac{17}{12}

3 0
3 years ago
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Name the property:
Neporo4naja [7]

Answer:

B. Commutative Property of Multiplication

Step-by-step explanation:

5 0
3 years ago
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Domain<br> Range<br><br><br> The above is ______
IRISSAK [1]

Answer:

Function.  

Domain:   {-3, 5, 3, -5}

Range:  {-6, 2, 1}

Step-by-step explanation:

The domain of the relation shown here is {-3, 5, 3, -5}.  Note how each of these elements is linked to ONLY ONE value in the range {-6, 2, 1}.  Because of that, we conclude that the table shown represents a function.

5 0
3 years ago
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