24 can go 3 times into 84
This is an Arithmetic Progression with 1st term 11 and common difference d=6
Number of Rows Number of seats Common difference " d"
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1st a₁ = 11
2nd a₁+d =17 d =2nd - 1st = 6
3rd a₁ +2d = 23 d =3rd - 2nd = 6
4th a₁ +3d = 29 d= 4th - 3rd = 6
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nth ROW a(n) = a₁ + (n-1)d
18th ROW a₁₈ = 11 + (18-1).6 = 11+(17)(6) = 113
General equation to predict the number of seat an the nth row:
Number of seats in nth row = a₁ + (n-1).d
X=-.25,-.5,-1,1,.5,.25
y=1,2,4,-4,-2,-1
Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
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X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
Answer:
o/3 or 1/1
Step-by-step explanation:
