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2 years ago

Business Loss A company loses $120 as a result of a shipping delay. The 8 owners of the

Mathematics

1 answer:

kow [346]2 years ago

7 0

$15 per person, i hope you have a good day :)

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A 100 serving of lasagna divided by 30 people

Misha Larkins [42]

Answer: 0.3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A recipe calls for 1 3/4 cups of bread flour and 1 2/3 cups of whole wheat flour. what is the total amount of flour used in the

Ivahew [28]

$1 \frac{3}{4} = 1.75 \\ 1 \frac{2}{3} = 1.66$
so
$1.75 + 1.66 = 3.41 \\ 3.41 = 3 \frac{5}{12}$

6 0

2 years ago

Kareem wrote the values shown below.

sweet [91]

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

[3.2] [2.7] [2.9] [4.8]

Since they are all of greatest integer functions i.e.

f(x) = [x]

It is known as greatest integer function whose value is always less than or equal to 'x'.

So, [3.2]=3

[2.7]=2

[2.9]=2

[4.8]=4

so, we can see that [2.7] and [2.9] is a equivalent pair.

Hence, Option 'B' is correct.

4 0

3 years ago

Read 2 more answers

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

Convert these unlike fractions to equivalent like fractions and add them. You must use the lcd to get the answer correct. If pos

ra1l [238]

Unlike fraction 1/7 is converted to equivalent like fraction 2/14 and the sum of 2/14 + 3/14 = 5/14.

As given in the question,

Given fraction is equal to:

1/7=? + 3/14=?

Here there are two fractions

1/7 and 3/14

LCD( least common denominator) of 7 and 14 is equal to 14.

Now make them like fractions

1/7 is equivalent to

( 1/7) × ( 2/2) = 2/ 14

Now 2/14 and 3/14 are like fractions

Sum of like fractions is:

2/14 + 3/14

= ( 2+ 3) / 14

= 5/ 14

Therefore, the conversion of unlike fraction 1/7 to like fraction is 2/14. And sum of 2/14 + 3/14 = 5/14.

The complete question is:

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If possible, reduce the final sum. 1/7=? + 3/14=?

Learn more about fractions here

brainly.com/question/10354322

#SPJ4

4 0

1 year ago