What’s the X intercept and Y intercept ?

World war 1 lasted from August 4th 1914 until November 11th, 1918. During this time an estimated 10 million lives were lost. Abo

Kryger [21]

The question is so dry, mechanical, and devoid of emotion
that it's terrifying.

There is no way to assign a number to "How many people were
dying per day", and I would prefer not even to think about it in
those terms.

-- The period of time from August 4, 1914 until November 11, 1918 is 1,560 days.

-- The "average", or better, the "unit rate" of 10 million events in 1,560 days
is the quotient

   (10,000,000 events) / (1,560 days)

   = 6,410.3 events per day

   = 267.1 events per hour

   =   4.45 events per minute.

Reciprocally, this is a unit rate of

13.48 seconds per event,
      sustained continuously for 4.274 years !

When will we ever learn ! ?

6 0

3 years ago

A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe

soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 87, thus $\mu = 87$ .
The standard deviation is of 25, thus $\sigma = 25$ .

Item a:

This probability is 1 subtracted by the p-value of Z when X = 60, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 87}{25}$

$Z = -1.08$

$Z = -1.08$ has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the p-value of Z when X = 110, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 87}{25}$

$Z = 0.92$

$Z = 0.92$ has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the p-value of Z when X = 110 subtracted by the p-value of Z when X = 60.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is 1 subtracted by the p-value of Z when X = 125, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125 - 87}{25}$

$Z = 1.52$

$Z = 1.52$ has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0

3 years ago

Barney & Noblet customers can choose to purchase a membership for $25 per year Members receive 10% off all store purchases

Law Incorporation [45]

Answer:

$70
y = 25 + 0.9x
$250

Step-by-step explanation:

1. 10% of $50 is $5, so the purchases would come to $50 -5 = $45. Added to the $25 membership fee, the total cost for the year would be

$45 +25 = $70

2. The member pays $25 even if no purchases are made. Then any purchases are 100% - 10% = 90% of the marked price. So, the total is ...

y = 25 + 0.90x

3. $25 is 10% of $250, so that is the amount the member would have to purchase to break even on cost.

If you like, you can compare the cost without the membership (x) to the cost with the membership (25+.9x) and see where those costs are equal.

x = 25 +0.9x . . . . . x is the spending level at which there is no advantage

0.1x = 25 . . . . . . . . subtract 0.9x

25/0.1 = x = 250 . . . divide by 0.1

4 0

3 years ago

Balance the equation

loris [4]

On the right side, there are

• 2•2 = 4 atoms of Nb

• 2•5 = 10 atoms of O

so among the reactants on the left, the reaction is balanced as

4 Nb + 5 O₂ → 2 Nb₂O₅

7 0

2 years ago

Given and which statement is correct? AB = FD AB < FD AB > FD AB ≤ FD

mojhsa [17]

Side AB is longer than side FD. Option (b) is correct.

Further explanation:

Given:

The options area as follows,

(a). $\overline {{\text{AB}}}$ and $\overline {{\text{FD}}}$ are the same length.

(b). $\overline {{\text{AB}}}$ is longer than $\overline {{\text{FD}}}.$

(c). $\overline {{\text{AB}}}$ is shorter than $\overline {{\text{FD}}}.$

(d). ${\text{AB}} \leqslant {\text{FD}}$

Explanation:

The sides opposite to equal angles are equal.

The side opposite to greater angle is greater than the other one.

The measure of $\angle {\text{DEC}}$ is ${65^ \circ }.$

The measure of $\angle {\text{BCA}}$ is ${72^ \circ }.$

$\angle {\text{BCA}}$ is greater than $\angle {\text{DEC}}$ . Therefore, the side opposite to greater angle is greater.

Side AB is longer than side FD. Option (b) is correct.

Option (a) is not correct.

Option (b) is correct.

Option (c) is not correct.

Option (d) is not correct.

Learn more:

Learn more about inverse of the function brainly.com/question/1632445.
Learn more about equation of circle brainly.com/question/1506955.
Learn more about range and domain of the function brainly.com/question/3412497.

Answer details:

Grade: High School

Subject: Mathematics

Chapter:Triangles

Keywords: relations, functions, all relation are functions, all functions are relations, no relations are functions, no functions are relation, one-to-one, onto, graph representation, paired, y-value, x-values, origin.

3 0

3 years ago

Read 2 more answers