Whats a real world problem for -5 times 5 equals -25
1 answer:
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Hello!
You can multiply (x-12) and (x+4)
x * x = x^2
x * 4 = 4x
-12 * x = -12x
-12 * 4 = -48
Now we have
x^2 - 8x - 48 = 9
Subtract 9 from both sides
x^2 - 8x -57 = 0
Use the quadratic formula
This give use the answer of
x = 4 +
Hope this helps!
You can multiply (x-12) and (x+4)
x * x = x^2
x * 4 = 4x
-12 * x = -12x
-12 * 4 = -48
Now we have
x^2 - 8x - 48 = 9
Subtract 9 from both sides
x^2 - 8x -57 = 0
Use the quadratic formula
This give use the answer of
x = 4 +
Hope this helps!
Answer:
The solution of the given equations
x =4 , y = 1
Step-by-step explanation:
<u>Explanation</u>:-
<u>Step(l</u>):-
Given the system of equations -5x+13y = -7 ..(l)
5x+4y=24 ..(ll)
<u>Step(ll)</u>
Adding (l) and (ll) equations and cancelling '5x' terms we get
13y+4y = -7 +24
17y = 17
dividing '17' on both sides, we get
y=1
<u>Step(lll):-</u>
Substitute y=1 in equation (l) , we get
-5x+13y = -7
-5x + 13(1) = -7
subtracting '13' on both sides, we get
-5x +13 -13= -7 -13
-5x = -20
Dividing '-5' on both sides, we get
x = 4
<u>Conclusion</u>:-
The solution of the given equations
x =4 , y = 1