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2 years ago

Shane hit the ball 3 out of times. How is this written as a ratio?

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

4 0

Question is incomplete as number of trials isn't given. We'll use an hypothetical value to make x plain the situation

Answer:

Kindly check explanation

Step-by-step explanation:

Given that the number of trials = x

If the number of tines the ball was hit out if 'x' trials = 3

The ratio of the number of hits to the number of trials is written as :

Number of hits : Number of trials

3 : x

Just put the exact value of x in the equation above and if possible, reduce to simplest form.

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Explain how to make a precise graph of y = -2x + 3 without making a T-Table.

kifflom [539]

Answer:

x 2 + 5 x + 6

Step-by-step explanation:

y = m x + c

y- intercept

x = 0

y = (-2) (0) + 3

(x =0, y = 3)

<h3>slope -2 </h3><h3>y = -1 x + 3</h3>

8 0

3 years ago

Write and solve an inequality that represents the values of x, in feet.

SVEN [57.7K]

Answer:

x < 16 ft

Step-by-step explanation:

Perimeter = x

If it is less than 16, the equation is:

x < 16

-Chetan K

3 0

2 years ago

sam and james win £500 in a competition. they share the money 3:7. sam gives 35% of the money he wins to his brother, harry. how

Black_prince [1.1K]

Sam gets (500/10)*3=150<span>£
harry gets (150/100)*35= 52.5</span>£

6 0

3 years ago

What’s the answer to (16-x)2?

Oxana [17]

Answer:

-x + 18

Step-by-step explanation:

just add 16 and 2. this is the furthest it can be simplified

6 0

3 years ago

Elizabeth attempts a field goal by kicking a football from the ground with an initial vertical

sammy [17]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}$

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.

5 0

3 years ago