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3 years ago

Can someone please help me !

Chemistry

1 answer:

Rama09 [41]3 years ago

6 0

This demonstration is most likely trying to show you potential energy. The rock is heavier than the pebble and will therefore displace more sand upon impact showing that the rock stores more potential energy than the pebble does when they are elevated to the same height (in this case the height is the height of the table).
This makes sense since potential energy is equal to mass times the acceleration due to gravity times height (PE=mgh) and the only thing that is changing is the mass of the object being suspended which means that the heavier object (the rock) will have more potential energy.

I hope this helps. Let me know if anything is unclear.

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Convert 1.05 x 1026 molecules Ni to number of moles.

vodka [1.7K]

Answer:

1077.3 molecular in 1.05*1026 molecules

4 0

3 years ago

is trying to plate gold onto his silver ring. He constructs an electrolytic cell using his ring as one of the electrodes. He run

notka56 [123]

Answer:

0.013 mole.

Explanation:

From the question given above, the following data were obtained:

Time (t) = 94.6 mins

Current (I) = 224.8 mA.

Mole of electrons (e) =?

Next, we shall convert 94.6 mins to seconds. This is illustrated below:

1 min = 60 s

Therefore,

94.6 mins = 94.6 min × 60 s / 1 min

94.6 mins = 5676 s

Thus, 94.6 mins is equivalent to 5676 s.

Next, we shall convert 224.8 mA to ampere (A). This can be obtained as follow:

1 mA = 1×10¯³ A

Therefore,

224.8 mA = 224.8 mA × 1×10¯³ A / 1 mA

224.8 mA = 0.2248 A

Thus, 224.8 mA is equivalent to 0.2248 A.

Next, we shall determine the quantity of electricity flowing in circuit. This can be obtained as follow:

Time (t) = 5676 s

Current (I) = 0.2248 A

Quantity of electricity (Q) =?

Q = it

Q = 0.2248 × 5676

Q = 1275.96 C

Finally, we shall determine the mole of electron by converting the quantity of electricity (i.e 1275.96 C) to number of electrons. This can be obtained as follow:

96500 C = 1 e

Therefore,

1275.96 C = 1275.96 C × 1 e / 96500 C

96500 C = 0.013 e

Thus, the mole of electron trasfered in the process is 0.013 mole.

3 0

3 years ago

1. What does a chemical change always result in?

Naddika [18.5K]

Answer:

1)New substance

2)Exothermic reaction(reaction which releases heat or light to the environment)

3)donate

4)buffers

5)salt(base)

6)NAOH

7)neutralisation reaction

8)It decreases

9)It is neutral

8 0

3 years ago

Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring

ludmilkaskok [199]

Answer:

1.20 V

Explanation:

$Pb(s) + Br_2(l)\rightarrow Pb^{2+}(aq) + 2Br^-(aq)$

Here Pb undergoes oxidation by loss of electrons, thus act as anode. Bromine undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

Given,

$Pb^{2+}(aq) + 2 e^-\rightarrow Pb(s)$

$E^0_{[Pb^{2+}/Pb]}= -0.13\ V$

$Br_2(l) + 2 e^-\rightarrow 2 Br(aq)$

$E^0_{[Br_2/Br^{-}]}=+1.07\ V$

$E^0=E^0_{[Br_2/Br^{-}]}- E^0_{[Pb^{2+}/Pb]}$

$E^0=+1.07- (-0.13)\ V=1.20\ V$

6 0

4 years ago

Somebody help me please i'm tired of trying to solve this problem ༎ຶ‿༎ຶ

Elenna [48]

Answer:

Q Line A

A: (a) 0 (b) 20

B: (b) 10 (c) 10

C: (c) 10 (d) 10

D: (d) 10 (e) 13

E: (e) 13 (f) 0

F: (f) 0 (g) 0

a: The velocity is whatever you need to see when you are specifically using a numberline so the answer for a is just 10

b: The velocity for this one is not as easy as the last one, its 7.

Explanation:

When you have a number line and your trying to find a numberline, you just have to subtract the smaller line to the largest number but if you are trying to find the velocity in beetween more than one thane you add the two biggest ones and subtract the smallest one and if you make a wrong move like add the biggest and smalles youll... still get the same answer so it doesnt matter really but its just easier to do the smallest one as the subtracting number just FYI. Happy spring break!

5 0

2 years ago