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expeople1 [14]
3 years ago
10

Help Ill give you the brainiest answer thing please just give me the right answer

Chemistry
2 answers:
Rudik [331]3 years ago
6 0
3rd I'm definitely sure
yaroslaw [1]3 years ago
5 0

Answer:

the 3rd one

Explanation:

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HELP!!1 ASAP PLEASE!!
coldgirl [10]

The correct matches are as follows:

1. Big Bang theory: Theory that suggests the origin of the universe started with an explosion and expansion of a very hot, dense, compact fireball.

2. Steady state theory: Theory about the origin of the universe that suggest that the universe has and will continue to be at a steady continuous state.

3. Oscillatory universe theory: Theory about the origin of the universe that suggests the universe is a never ending cycle of expansion and contraction.

4. Nebular theory: Theory about the origin of the solar system that suggest our sun and planet formed from a cloud of dust and gas.

5. Inflation theory: Theory that upholds the big bang theory but suggest there was an extremely rapid expansion or inflation milliseconds after the big bang.

6. Condensation theory: Theory about the origin of the solar system that agree with the nebular theory but stresses the importance of interstellar dust in planet formation.

5 0
4 years ago
Can you describe the situations when Greek prefixes are used?
Black_prince [1.1K]

Answer:

Here's what I get  

Explanation:

At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.

They indicate the number of atoms or groups in a molecule when you are naming a compound.

1. Binary covalent compounds

For example, P₂S₅ is diphosphorus pentasulfide.

2. Hydrates

For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.

7 0
3 years ago
Which of the following compounds would be named with a name that ends in -ene?
aliina [53]
Alkene is the group of hydrocarbon molecules that contains at least one double bond. So, A, C and D would be named ending with -ene. 
5 0
3 years ago
Use a volumetric flask to prepare 100.00 mL of 0.70M HCl solution. Do this by diluting either one of the stock hydrochloric acid
Orlov [11]

Answer:

- Take 3.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.

- Take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL

Explanation:

Hello,

In this case, given that the dilutions are preparedfrom 3.0-M and 6.0-M hydrochloric acid, we must proceed as follows:

- 3.0-M stock: when using this stock, the aliquot you must take is computed as shown below:

V_1=\frac{M_2V_2}{M_1}=\frac{100.00mL*0.70M}{3.0M}=23.3mL

It means that you must take 23.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.

- 6.0-M stock: when using this stock, the aliquot you must take is computed as shown below:

V_1=\frac{M_2V_2}{M_1}=\frac{100.00mL*0.70M}{6.0M}=11.7mL

It means that you must take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL.

Regards.

3 0
3 years ago
If you have A 6-g sugar cube (C12H22011) and dissolved in a cup of hot tea. The
Iteru [2.4K]

The percentage of sugar in the solution is 1%

To solve this question, we need to find the percentage of 6 out of 600.

Data given;

  • mass of sugar = 6g
  • mass of solution = 600g
<h3 /><h3>What is Percentage</h3>

This is the rate or proportion of a substance in the total value and multiplied by 100.

The percentage of sugar in the solution is calculated by

\frac{6}{600} * 100 = 1 %

The percentage of sugar in the solution is 1%

Learn more about percentage here;

brainly.com/question/251701

8 0
3 years ago
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