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masya89 [10]
3 years ago
14

How did seed availability affect traits of individuals in the medium ground finch population of the galapagos islands

Chemistry
1 answer:
vodomira [7]3 years ago
8 0
A little background may help understand this question better: The Galapagos Islands is home to a lot of species but particular interest here is only the finches and their beak sizes. We have the cactus finch that has a long beak well suited for accessing blossoms; the tree finch with parrot-shaped beaks suited for finding insects underneath the barks of trees; and, the ground finch with beaks suited for eating seeds.

Grant and colleagues studied the medium ground finch in order to observe natural selection at work. Medium ground finch were perfect to study because the only major factor that affected their hypothesized evolution was the climate, which <em>affected food availability. </em>The researchers observed that when food became scarce and only <em>large seeds were present</em><em>, </em>only the finch with bigger beaks were able to survive. Those with smaller beaks died of starvation because they could not eat the big seeds. Time went on, and when the researchers measure beak size, they found a significant change in size compared to previous generations.
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A cube with sides 3cm.Its mass is 54g. will it sink or float
zloy xaker [14]

Answer:

It will sink.

Explanation:

Density of water=1gm/cc (In CGS)

Volume of cube=l^3 =3^3= 27cc

Mass of cube =54gm

Density of cube=M/V =54/27 =2gm/cc

Here, density of cube is greater than that of water. So, the cube sinks.

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3 years ago
Please. help. me!!!!!!!!!!! I don't have all the sources to figure this one out!
Anon25 [30]

Answer:

The answer to your question is below

Explanation:

Element      Atomic number   Atomic mass   # proton   # neutron  # electron

Copper           29                          64                    29              35              29

Fluorine            9                           19                      9               10                9

Lead              82                        207.2                  82            125               82

Sodium          11                            23                     11                12                11

Nitrogen          7                            14                      7                 7                 7

47.- Atomic number, Atomic mass, number of protons, neutrons and electrons

48.- Element, atomic mass, number of protons, neutrons and electrons

49.- Element, atomic number, atomic mass, neutrons and electrons

50.- element, atomic number, atomic mass, protons and neutrons

51.- element, atomic number, protons, neutrons and electrons

                           

3 0
3 years ago
What does a TRAAP test stand for
Aleks [24]

Answer:

TIMELINESS, RELEVANCE, AUTHORITY, ACCURACY and PURPOSE.

Explanation:

hope it helps!

7 0
3 years ago
Read 2 more answers
tert-Butyl alcohol is a solvent with a Kf of 9.10 ∘C/m and a freezing point of 25.5 ∘C. When 0.807 g of an unknown colorless non
Lina20 [59]

Answer:

ethylene glycol (molar mass = 62.07 g/mol).

Explanation:

  • We can solve this problem using the relation:

<em>ΔTf = Kf.m,</em>

ΔTf is the depression in the freezing point of tert-Butyl alcohol (ΔTf = freezing point of pure solvent - freezing point in presence of unknown liquid = 25.5°C - 15.3°C = 10.2°C).

Kf is the molal freezing point constant of tert-Butyl alcohol (Kf = 9.1 °C/m).

m is the molality of unknown liquid.

∵ ΔTf = Kf.m

<em>∴ m = ΔTf/Kf </em>= (10.2°C)/(9.1 °C/m) = <em>1.121 m.</em>

  • We need to calculate the molar mass of the unknown liquid:

Molality (m) is the no. of moles of solute in 1.0 kg of solvent.

∴ m = (mass/molar mass) of unknown liquid/(mass of tert-Butyl alcohol (kg))

m = 1.121 m, mass of unknown liquid = 0.807 g, mass of tert-Butyl alcohol = 11.6 g = 0.0116 kg.

<em>∴ molar mass of unknown liquid = (mass of unknown liquid)/(m)(mass of tert-Butyl alcohol (kg)) </em>= (0.807 g)/(1.121 m)(0.0116 kg) = <em>62.06 g/mol.</em>

<em></em>

  • So, the unknown liquid is:

<em>ethylene glycol (molar mass = 62.07 g/mol).</em>

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