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masya89 [10]
3 years ago
14

How did seed availability affect traits of individuals in the medium ground finch population of the galapagos islands

Chemistry
1 answer:
vodomira [7]3 years ago
8 0
A little background may help understand this question better: The Galapagos Islands is home to a lot of species but particular interest here is only the finches and their beak sizes. We have the cactus finch that has a long beak well suited for accessing blossoms; the tree finch with parrot-shaped beaks suited for finding insects underneath the barks of trees; and, the ground finch with beaks suited for eating seeds.

Grant and colleagues studied the medium ground finch in order to observe natural selection at work. Medium ground finch were perfect to study because the only major factor that affected their hypothesized evolution was the climate, which <em>affected food availability. </em>The researchers observed that when food became scarce and only <em>large seeds were present</em><em>, </em>only the finch with bigger beaks were able to survive. Those with smaller beaks died of starvation because they could not eat the big seeds. Time went on, and when the researchers measure beak size, they found a significant change in size compared to previous generations.
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Need help with this question
devlian [24]

Answer:

c

Explanation:

5 0
3 years ago
Before we can use this equation for
AlexFokin [52]

Answer:

2C₂H₆ +  [7]O₂     →      [4]CO₂ + [6]H₂O

Explanation:

Chemical equation:

C₂H₆ +  O₂     →      CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C = 1

H = 12                                    H = 2

O = 2                                     O = 3

Step 2:

2C₂H₆ +  O₂     →      4CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

3 0
3 years ago
Classify these salts as acidic, basic, or neutral. KCL, NH4Br, K2CO3, NaCN, LiClO4? This is what I put but got it wrong: KCl = b
MaRussiya [10]
In classifying salts as neutral, acidic, or basic, it is important to take note of the strength of the acids and bases that they come from. A strong acid and strong base produce a neutral salt. A weak acid and strong base produce a basic salt. A strong acid and weak base produce an acidic salt. So the answers must be:

KCl = neutral (from HCl and KOH)
NH4Br = acidic (from NH4 and HBr)
K2CO3 = basic (from KOH and H2CO3)
NaCN = basic (from NaOH and HCN)
LiClO = basic (from LiOH and HClO)
3 0
4 years ago
Read 2 more answers
Convert 22 grams of copper Il chloride (Cucl2) to moles. <br>with work please ​
Fittoniya [83]
Hope this helps!

https://youtu.be/MT5tKijKZwQ
5 0
3 years ago
Read 2 more answers
IMESSAGE GAMES ANYONE?
Yuki888 [10]
Lollllllllllllllllllll
3 0
3 years ago
Read 2 more answers
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