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3 years ago

What was the physical property used by mendleev in creating his periodic table.

Chemistry

1 answer:

shtirl [24]3 years ago

5 0

Answer:

melting point and boiling point

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A gas sample occupies 2.1 L at a pressure of 101 kPa.

Verizon [17]

Answer:

D) 0.9 L

Explanation:

At constant temperature,

PV = Constant

so,

P1.V1 = P2. V2

101 × 2.1 = 235 × V2

V2 = 0.9 L

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3 years ago

Read 2 more answers

Calculate the percentage error in the molar mass of our natural gas which is 16.9g/mol

taurus [48]

Answer:

no examination in 16.9g in molicube i n gas

Explanation:

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3 years ago

How does stem apply to science? (i swear if yall just answer for points ima lose it)

vova2212 [387]

STEM is an acronym meaning

Science

Technology

Engineering

Mathematics

One of the main focuses of STEM courses is on science, so you will be learning about various types of science

This is an approach at learning to have students learn all four types of subjects in one class, based on real world applications.

8 0

3 years ago

2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo

pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

Chemical reaction involved: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: $Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2$

To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:

$\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}$

$\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)$

$\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)$

Therefore, the Gibb's free energy change at 37° C (310.15 K): ΔG = (-2.45 kJ/mol)

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3 years ago

How do felsic igneous rocks

Svetradugi [14.3K]

Answer:

A. Felsic igneous rocks are less dense than mafic igneous rock

Explanation:

"Felsic rocks are composed of larger quantities of silicates and therefore are less dense. Felsic magma is less dense and more viscous than mafic magma." - study.com

8 0

2 years ago

What was the physical property used by mendleev in creating his periodic table.​

What was the physical property used by mendleev in creating his periodic table.