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Andru [333]
3 years ago
7

Help me on this question please

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
The answer is A. 6

Hope I am right
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meriva
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4 0
3 years ago
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
Mrs.Welch needs to buy some cat food . If each can costs $0.79 and she has a coupon for $2 off the entire purchase, how many can
allochka39001 [22]

Answer:

11 cans of cat food...........

Step-by-step explanation:

£0.79 x 11 = £8.69

£8.69 - £2 = 6.69

6 0
3 years ago
Read 2 more answers
Does anyone know how to do this, i’ll give you brainliest and there’s 16 points
leva [86]

6y-4=4y+2

2y=6, so y=3.

Plugging it in, you get that AC equals 4*3+2=14.

This is an isosceles triangle.


6 0
3 years ago
The radius of the circular track was 157.64 feet find the circumference of the track
DerKrebs [107]
Before we solve for anything, let's remember what our formula is.

The circumference of a circle is 2PiR (2 x Pi x R).

Our radius is 157.64.
Pi is 3.14 (estimated).

Let's plug our numbers into the formula.

Circumference = 2 x 3.14 x 157.64.
2 x 3.14 = 6.28
6.28 x 157.64 = 989.979 (990 if estimated).

Your circumference is:
989.979 ft^2.

I hope this helps!
7 0
3 years ago
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