Answer:
50.24
Step-by-step explanation:
The first step is to find the area of it if it was a whole circle
you get this by squaring the radius
8*8 or 8^2= 64
then, you have to multiply it by 3.14 which gives you
200.96.
Then divide it by 4 to get a quarter of the circle to get the final answer
50.24
Hope this helps, if it does, please give me brainliest, it will help a lot :)
Have a good day
Answer:
hey I believe standard form would look like this: f(x) = a(x - h)^2 + k
this is regular form f(x)=ax^2+bx+c or something like x^2+4x+4.
I think H and K are the vertex
hope this is close to what your looking for.
Step-by-step explanation:
I think it's x^2+6x-18
Answer:
247 ft is the correct answer
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫
➷ 9=5x-3+9
First, you would need to combine the like terms.
-3+9 = 6
9=5x+6
Next, you subtract 6 on both sides.
3=5x
Finally, you divide 5 on both sides to isolate x.
3/5=x
Final answer:
x=3/5
✽
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
TROLLER
Given:
The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).
To find:
The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.
Solution:
If a figure reflected across the line x=a, then
![(x,y)\to (-(x-a)+a,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%28-%28x-a%29%2Ba%2Cy%29)
![(x,y)\to (-x+a+a,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%28-x%2Ba%2Ba%2Cy%29)
![(x,y)\to (2a-x,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%282a-x%2Cy%29)
The triangle after a reflection over x = -3. So, the rule of reflection is
![(x,y)\to (2(-3)-x,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%282%28-3%29-x%2Cy%29)
![(x,y)\to (-6-x,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%28-6-x%2Cy%29)
The vertices of triangle after reflection are
![R(3,7)\to R'(-6-3,7)](https://tex.z-dn.net/?f=R%283%2C7%29%5Cto%20R%27%28-6-3%2C7%29)
![R(3,7)\to R'(-9,7)](https://tex.z-dn.net/?f=R%283%2C7%29%5Cto%20R%27%28-9%2C7%29)
Similarly,
![S(-5,-2)\to S'(-6-(-5),-2)](https://tex.z-dn.net/?f=S%28-5%2C-2%29%5Cto%20S%27%28-6-%28-5%29%2C-2%29)
![S(-5,-2)\to S'(-6+5,-2)](https://tex.z-dn.net/?f=S%28-5%2C-2%29%5Cto%20S%27%28-6%2B5%2C-2%29)
![S(-5,-2)\to S'(-1,-2)](https://tex.z-dn.net/?f=S%28-5%2C-2%29%5Cto%20S%27%28-1%2C-2%29)
And,
![T(3,-5)\to T'(-6-3,-5)](https://tex.z-dn.net/?f=T%283%2C-5%29%5Cto%20T%27%28-6-3%2C-5%29)
![T(3,-5)\to T'(-9,-5)](https://tex.z-dn.net/?f=T%283%2C-5%29%5Cto%20T%27%28-9%2C-5%29)
Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).