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Dahasolnce [82]
3 years ago
8

ILL MARK U BRAINLIEST!!!

Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0

Answer:

Step-by-step explanation:

B

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Step-by-step explanation:

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The Ishares Bond Index fund (TLT) has a mean and annual standard deviation of returns of 5%
rodikova [14]

Answer:

C) (-5%.15%)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =10\%=0.1 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=5% =0.05 represent the population standard deviation  

2) Confidence interval

We assume that the random variable X who represent The Ishares Bond Index fund (TLT) follows this distribution:

X \sim N(\mu, \sigma=10\%=0.1)

The confidence interval for the returns on TLT is given by the following formula:

\bar X \pm z_{\alpha/2}\sigma   (1)

In order to calculate the critical value z_{\alpha/2}. Since the Confidence is 0.66 or 66%, the value of \alpha=0.34 and \alpha/2 =0.17, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.17,0,1)".And we see that z_{\alpha/2}=0.95

Now we have everything in order to replace into formula (1):

0.05-0.95(0.1)=-0.05    

0.05+0.95(0.1)=0.15

So on this case the 66% confidence interval would be given by (-0.05;0.15) and we can convert this into % and wr got (-5%; 15%).    

3 0
4 years ago
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