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denis-greek [22]
3 years ago
7

28)

Chemistry
2 answers:
White raven [17]3 years ago
6 0

Answer:

D [polymers]

Explanation:

The joining of monomers (small molecules) is polymerization.

Ksju [112]3 years ago
6 0
The answer is c gluecose
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How does heat move from one place to another on the troposphere
d1i1m1o1n [39]

I thinlk it's by radiation?......

8 0
4 years ago
What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.
zloy xaker [14]
For the equation to be balanced, the Atom's coefficient on the left side and the right side of the equation has to be equal

so, the answer would be : 

Br2 + S2032- + 5H20 -- >  BR2- + 2S02- + H+

Hope this helps
8 0
3 years ago
Name two compounds with more exothermic lattice energies than scandium oxide and justify your choice.
N76 [4]

Answer:

1 . Al_2O_3

2. TiO_2

Explanation:

The more stable the ionic compound, the more is it lattice energy.

  • The more the charge on the cation and the anion, the greater is the lattice energy.
  • The less the size of the cation and the anion, the greater is the lattice energy.

Scandium oxide (Sc_2O_3) is an oxide in which Sc^{3+} behaves as cation and O^{2-} behaves as anion.

The compounds which has higher lattice energy than scandium oxide are:

1 . Al_2O_3

This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation Al^{3+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

2. TiO_2

This is because the charge on the cation Ti^{4+} is greater than that of Sc^{3+} and also the size of the cation Ti^{4+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

3 0
3 years ago
What element decreases its oxidation number in this reaction
MissTica

Where’s the reaction?

8 0
3 years ago
Read 2 more answers
If 3.00 mL of 0.0250 M CuSO4 is diluted to 25.0 mL with pure water, what is the molarity of copper(II) sulfate in the diluted so
g100num [7]

Answer:

0.00268 M

Explanation:

To find the new molarity, you need to (1) find the moles of CuSO₄ (via the molarity equation using the beginning molarity and volume) and then (2) find the new molarity (using the moles and combined volume). Your final answer should have 3 sig figs to match the given values.

<u>Step 1:</u>

3.00 mL / 1,000 = 0.00300 L

Molarity = moles / volume (L)

0.0250 M = moles / 0.00300 L

(0.0250 M) x (0.00300 L) = moles

7.50 x 10⁻⁵ = moles

<u>Step 2:</u>

25.0 mL / 1,000 = 0.0250 L

0.0250 L + 0.00300 L = 0.0280 L

Molarity = moles / volume (L)

Molarity = (7.50 x 10⁻⁵ moles) / (0.0280 L)

Molarity = 0.00268 M

8 0
2 years ago
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