Answer:
He responded by saying their business definition was far too narrow.
Explanation:
Williams Bryan relates the battle for free silver with the revolution in the United States.
His iconic "Cross of Gold" address ignited the Democratic National Convention in 1896 where he begged the american people not to be "crucified on the cross of gold." He was said this because of the Republicans plan to introduce a firm gold standard and abolish silver coinage.
The Orbital configuration for Manganese is as follows:
1s2 2s2 2p6 3s2 3p6 4s2 3d5
It says 3d is shown with five orbitals- this is correct
Then it says the first two orbitals have two electrons-this is incorrect.
When filling in the orbitals for any element, you first need to distribute to ALL orbitals then extras go from there.
The orbital d can have up to 10 electrons so you need to distribute at least one electron to all ten. Since you only have 5 then only 5 orbitals would have electrons in them. In order for ANY of the orbitals to have two electrons, there would need to be AT LEAST 11 electrons to distribute.
The grams of aluminium oxide are formed when 350 kj heat are released is calculated as follows
1mole = 850Kj
what about 350kj
=1mole x350/850 = 0.412 moles
mass of Al = moles of Al x molar mass of Al
= 0.412mol x 27 g/mol = 11.124 grams
1) We need to convert 12.0 g of H2 into moles of H2, and <span> 74.5 grams of CO into moles of CO
</span><span>Molar mass of H2: M(H2) = 2*1.0= 2.0 g/mol
Molar mass of CO: M(CO) = 12.0 +16.0 = 28.0 g/mol
</span>12.0 g H2 * 1 mol/2.0 g = 6.0 mol H2
74.5 g CO * 1 mol/28.0 g = 2.66 mol CO
<span>2) Now we can use reaction to find out what substance will react completely, and what will be leftover.
CO + 2H2 -------> CH3OH
1 mol 2 mol
given 2.66 mol 6 mol (excess)
How much
we need CO? 3 mol 6 mol
We see that H2 will be leftover, because for 6 moles H2 we need 3 moles CO, but we have only 2.66 mol CO.
So, CO will react completely, and we are going to use CO to find the mass of CH3OH.
3) </span>CO + 2H2 -------> CH3OH
1 mol 1 mol
2.66 mol 2.66 mol
4) We have 2.66 mol CH3OH
Molar mass CH3OH : M(CH3OH) = 12.0 + 4*1.0 + 16.0 = 32.0 g/mol
2.66 mol CH3OH * 32.0 g CH3OH/ 1 mol CH3OH = 85.12 g CH3OH
<span>
Answer is </span>D) 85.12 grams.
