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snow_tiger [21]
3 years ago
10

If you used the method of initial rates to obtain the order for no2, predict what reaction rates you would measure in the beginn

ing of the reaction for initial concentrations of 0.200 m, 0.100 m, & 0.050 m no2.
Chemistry
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

Rate law is: Rate = k[NO2]^2 = 10 x [NO2]^2

When [NO2] = 0.200 M:

Rate = 10 x 0.200^2 = 0.400 M/s

When [NO2] = 0.100 M:

Rate = 10 x 0.100^2 = 0.100 M/s

When [NO2] = 0.050 M:

Rate = 10 x 0.050^2 = 0.0250 M/s

Explanation:

If you used the method of initial rates to obtain the order for no2, predict what reaction rates you would measure in the beginning of the reaction for initial concentrations of 0.200 m, 0.100 m, & 0.050 m no2.

Rate law is: Rate = k[NO2]^2 = 10 x [NO2]^2

When [NO2] = 0.200 M:

Rate = 10 x 0.200^2 = 0.400 M/s

When [NO2] = 0.100 M:

Rate = 10 x 0.100^2 = 0.100 M/s

When [NO2] = 0.050 M:

Rate = 10 x 0.050^2 = 0.0250 M/s

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Answer:

9.64g

Explanation:

The balanced equation for the reaction is given below:

2NH3 (g) —> 3H2 (g) + N2 (g)

Next, we need to calculate the mass NH3 that decomposed and the mass of H2 produced from the balanced equation. This is illustrated below:

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 that decomposed from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 produced from the balanced equation = 3 x 2 = 6g.

Now, we can obtain the mass of H2 formed from 54.6g of NH3 as follow:

From the balanced equation above,

34g of NH3 decomposed to produce 6g of H2.

Therefore, 54.6g of NH3 will decompose to produce = (54.6x6)/34 = 9.64g of H2

Therefore, 9.64g of H2 can be obtained from 54.6g of NH3.

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Place the parts of the human circulatory system in order from highest to lowest degree of internal organization.
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cell tissue organ and system

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The regular sequence of growth and division that cells undergo is called the?
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Answer:

Cell cycle.

Explanation:

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A unicellular organism refers to a living organism that possess a single-cell while a multicellular organism has many (multiple) cells.

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2 years ago
how many grams of oxygen are produced if 25.0g of potassium chlorate decomposes according to the reaction 2KCLO3 —-> 2KCL +3O
AveGali [126]

Answer:

approximately 15.1 grams.

Explanation:

The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want.

change 25 grams of potassium chlorate to moles.

calculate the gram molecular mass of potassium chlorate.

Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron.

1 K x 39 grams/mole

+1 Cl x 35.4 grams/ mole

+3 O x 16 grams/ mole

= 122.4 grams / mole Potassium Chlorate

25

122.4

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2.05 moles of Potassium Chlorate.

There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride.

2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride.

Find the gram molecular mass of Potassium Chloride.

1 K x 39 = 39

+1 Cl x 35.4 = 35.4

= 74.4 grams / mole.

2.05 moles x 74.4 grams/ mole = 15.2 grams

Hope it helps :)

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