Ask question

Ask question

All categories

snow_tiger [21]

3 years ago

10

If you used the method of initial rates to obtain the order for no2, predict what reaction rates you would measure in the beginn

ing of the reaction for initial concentrations of 0.200 m, 0.100 m, & 0.050 m no2.

1 answer:

luda_lava [24]3 years ago

8 0

Answer:

Rate law is: Rate = k[NO2]^2 = 10 x [NO2]^2

When [NO2] = 0.200 M:

Rate = 10 x 0.200^2 = 0.400 M/s

When [NO2] = 0.100 M:

Rate = 10 x 0.100^2 = 0.100 M/s

When [NO2] = 0.050 M:

Rate = 10 x 0.050^2 = 0.0250 M/s

Explanation:

If you used the method of initial rates to obtain the order for no2, predict what reaction rates you would measure in the beginning of the reaction for initial concentrations of 0.200 m, 0.100 m, & 0.050 m no2.

Rate law is: Rate = k[NO2]^2 = 10 x [NO2]^2

When [NO2] = 0.200 M:

Rate = 10 x 0.200^2 = 0.400 M/s

When [NO2] = 0.100 M:

Rate = 10 x 0.100^2 = 0.100 M/s

When [NO2] = 0.050 M:

Rate = 10 x 0.050^2 = 0.0250 M/s

You might be interested in

Write the equation for the neutralization reaction in which barium chloride is the salt formed. Show the reaction in which the f

frutty [35]

Answer:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

Explanation:

In a complete neutralization reaction, an acid reacts with a base to form neutral salt and water. To form barium chloride, hydrochloric acid (acid) reacts with barium hydroxide (base). The balanced chemical equation is:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

8 0

3 years ago

Under the same conditions of solar radiation, compared with oceans the land will warm_________

aksik [14]

Land will warm faster/quicker

7 0

3 years ago

You add 100.0 g of water at 52.0 °C to 100.0 g of ice at 0.00 °C. Some of the ice melts and cools the water to 0.00 °C. When the

lara31 [8.8K]

Answer:

$m_{ice} = 65.336\,g$

Explanation:

Accoding to the First Law of Thermodynamics, the heat released by the water melts a portion of ice. That is to say:

$Q_{water} = Q_{ice}$

$(100\,g)\cdot \left(4.184\,\frac{J}{kg\cdot ^{\textdegree}C}\right)\cdot (52\,^{\textdegree}C - 0\,^{\textdegree}C) = m_{ice}\cdot \left(333\,\frac{J}{g} \right)$

The amount of ice that is melt is:

$m_{ice} = 65.336\,g$

5 0

3 years ago

what volume of co2 is produced at stp when 270g of glucose are consumed in the following reaction? c6h12o6 + 6o2(g) -> 6co2 (

lana [24]

Answer:

202 L

Explanation:

Step 1: Write the balanced equation

C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

270 g × 1 mol/180.16 g = 1.50 mol

Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose

The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol

Step 4: Calculate the volume of 9.00 moles of CO₂ at STP

The volume of 1 mole of an ideal gas at STP is 22.4 L.

9.00 mol × 22.4 L/mol = 202 L

4 0

3 years ago

How much heat (in kj) is released when 3.600 mol naoh(s) is dissolved in water? (the molar heat of solution of naoh is â445.1 kj

Fantom [35]

<span>-1602 kj

Sauce:me

Your welcome
</span>

8 0

3 years ago

Read 2 more answers