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3 years ago

Help me pleaseeee:

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

8 0

Answer:

8t-3 ≥ 569.

Step-by-step explanation:

'T' represents the number of hours.

'-3' represents the amount paid for equipment fees.

When solved, we get:

8t ≥ 572

t ≥ 71.5 hours.

Sloan [31]3 years ago

6 0

Answer:

8t+3>569

Step-by-step explanation:

i think this is right

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Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly

kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =9004$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=20-1=19$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that $t_{\alpha/2}=2.86$

Now we have everything in order to replace into formula (1):

$9004-2.86\frac{5629}{\sqrt{20}}=5004.168$

$9004+2.86\frac{5629}{\sqrt{20}}=12603.832$

So on this case the 99% confidence interval would be given by (5004.168;12603.832)

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0

3 years ago

Olivia goes to Egypt and saw a model of triangle shaped pyramid. She enlarging using a scale factor of 1.2. What will be the per

ivann1987 [24]

If you are talking about the area and perimeter of one of the triangular faces...
8 x 1.2 = 9.6
6 x 1.2 = 7.2

Perimeter = 9.6 + 7.2 + 7.2 = 24
Area = Linear Scale Factor²
1.2² = 1.44
7 x 1.44 = 10.08 (units)²

8 0

3 years ago

Fr plz help i give brainiest

xz_007 [3.2K]

Answer:

Hello Love! Answer: 8000

volume is just length x width x height

so 20 x 20 x 20 = 8000

5 0

3 years ago

Read 2 more answers

A fair coin is tossed and a single number cube is rolled. the probability of rolling a number less than 5 is ________________. t

Alik [6]

You have a 4/ 6 chance
then you have a 2/6 chance if the number is an odd number then reducing you would get
1. 2/3
2. 1/3

7 0

3 years ago

A college chemistry instructor thinks the use of embedded tutors will improve the success rate in introductory chemistry courses

Yuliya22 [10]

Answer:

Step-by-step explanation:

Hello!

The chemistry instructor tested the hypothesis that the proportion of students that passed the introductory chemistry class is better with an embedded. If the known proportion for this population is 65%, the tested hypothesis is:

H₀: p=0.65

H₁: p>0.65

The calculated statistic is Z=2.52 and the associated p-value: 0.0059

Remember:

The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

In this case:

P(Z≥2.52)=0.0059

There is no significance level, the most common one is α: 0.05 so I'll use it as an example.

To make a decision using the p-value you have to compare it to the α.

If p- value>α then you support the null hypothesis (In this case, you can say that there is no change in the proportion of students that passed the introductory chemistry class with an embedded tutor.)

If p-value≤α your decision will be to reject the null hypothesis (In this case, there is significant evidence to say that there is an improvement in the success rate of the introductory chemistry class with an embedded tutor?

Since the p-value:0.0059 is less than the significance level 0.05, you will decide to reject the null hypothesis.

I hope you have a SUPER day!

8 0

3 years ago