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2 years ago

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Hi everyone, I'm having trouble with these questions and I'm not sure how to do them/where to start. Does anyone have a solution

to it? It will help me with my future problems on this topic!

1 answer:

Iteru [2.4K]2 years ago

3 0

Answer:

sounds simple, but getting to know people can be seriously hard. We've got some tips to help you ease the process and get to know people ...

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Question60 is 40% of what number?

Natalka [10]

let the required number be x then

$\begin{gathered} \frac{60}{x}\times100=40 \\ x=\frac{60}{40}\times100 \\ x=150 \end{gathered}$

So 60 is 40% of 150.

7 0

1 year ago

Tickets to a school play cost $1.50 for a student and $2.50 for an adult. Clara sold 5 tickets for a total of $10.50. How many o

joja [24]

<span> 2 student tickets
</span><span>=1.50+1.50+2.50+2.50+2.50=10.50</span>

6 0

2 years ago

Identify whether each phrase is an expression, equation, or inequality.

OverLord2011 [107]

Answer:

swich the one attached to equation with the one attached to expression

Step-by-step explanation:

an equation need to have an equals sign, an expression doesnt.

8 0

3 years ago

Read 2 more answers

A bag contains 5 2/5kg of sand. The bag has a hole in it. Every 10 minutes, 1 2/3kg of sand escapes from the bag. After 20 minut

fenix001 [56]

Quantify of sand in a bag =

$= \: 5 \frac{2}{5} \ \:$

$= \frac{(5 \times 5 +2) }{5}$

$= \frac{27}{5} \: kg$

Quantity of sand that escapes in every 10 minutes :-

$= 1 \frac{2}{3} kg$

Quantity of sand that will escape in 20 minutes :-

$= 1 \frac{2}{3} \times 2$

$= \frac{(3 \times 1 + 2)}{3} \times 2$

$= \frac{5}{3} \times 2$

$= \frac{10}{3}$

Quantity of sand that will remain in the sand bag :-

$= \frac{27}{5} - \frac{10}{3}$

$= \frac{(27 \times 3)}{15} - \frac{(10 \times 5)}{15}$

$= \frac{81}{15} - \frac{50}{15}$

$= \frac{31}{15}$

$= 2 \frac{1}{5} \: kg$

$therefore \: , \: 2 \frac{1}{5} \: kg \: sand \: is \: left \: in \: the \: bag \: .$

3 0

3 years ago

A polygon has its vertices at the following points.

seropon [69]

Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

$\sqrt{(x2-x1)^2 + (y2 -y1)^2}$

AB = $\sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}$

BC = |7-4| = 3

CD = $\sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}$

AD = |9-2| = 7

2) equation of the line that passes threw BC

y = 7

3) equation of the line that passes threw AD

y = 5

conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

3 0

2 years ago