Y=kx, k is not equal to 0
when y=32,x=3, 32=3k
k=32/3
so y=32/3*x
when y=15, 15=32/3*x
x=45/32
9514 1404 393
Answer:
(-2, -3), (1, 6), (2, 9) are plotted in the attached graph
Step-by-step explanation:
For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).
For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).
For x = 2, y = 3(2) +3 = 9. The ordered pair is (2, 9).
The graph is attached.
<span>Width = 6
Length = 30
We know the perimeter of a rectangle is simply twice the sum of it's length and width. So we have the expression:
72 = 2*(L + W)
And since we also know for this rectangle that it's length is 6 more than 4 times it's width, we have this equation as well:
L = 6 + 4*W
So let's determine what the dimensions are. Since we have a nice equation that expresses length in terms of width, let's substitute that equation into the equation we have for the perimeter and solve. So:
72 = 2*(L + W)
72 = 2*(6 + 4*W + W)
72 = 2*(6 + 5*W)
72 = 12 + 10*W
60 = 10*W
6 = W
So we now know that the width is 6. And since we have an expression telling us the length when given the width, we can easily determine the length. So:
L = 6 + 4*W
L = 6 + 4*6
L = 6 + 24
L = 30
And now we know the length as well.</span>
X-int: none
Y-int: (0,27)
Vertex: (-3,18)
AOS: x= -3
Max & Min Value: (-3,18)
Answer:
a. [6.6350,7.3950]
b. ME=0.5150
Step-by-step explanation:
a. Given that n=40,
and that:
The required 90% confidence interval can be calculated as:
![\bar x\pm(margin \ of \ error)\\\\\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\6.88\pm(1.645\times \frac{1.98}{\sqrt{40}})\\\\=[6.3650,7.3950]](https://tex.z-dn.net/?f=%5Cbar%20x%5Cpm%28margin%20%5C%20of%20%5C%20error%29%5C%5C%5C%5C%5Cbar%20x%5Cpm%20z_%7B%5Calpha%2F2%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5C6.88%5Cpm%281.645%5Ctimes%20%5Cfrac%7B1.98%7D%7B%5Csqrt%7B40%7D%7D%29%5C%5C%5C%5C%3D%5B6.3650%2C7.3950%5D)
Hence, the 90% confidence interval for the population mean cash value of this crop is [6.6350,7.3950]
b. The margin of error at 90% confidence interval is calculated as:

Hence, the margin of error is 0.5150