–3y9 number of terms

Mathematics

1 answer:

qwelly [4]3 years ago

5 0

Answer and Step-by-step explanation:

$-3y^{9}$

This value above is ONE term. Even though it is made up of more values and stuff, it is all one term BECAUSE they are all connect, so the -3 is with the y by multiplication, and the 9 is with -3y as an exponent of y.

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the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width

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Length and width of rectangle is 15 inches and 6 inches respectively

<h3>Solution:</h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

The formula for area of rectangle is given as:

$\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}$

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

$\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}$

On solving the above expression for x we get

$\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}$

$\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}$

Hence length and width of rectangle is 15 inches and 6 inches.

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