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const2013 [10]
4 years ago
14

How do I solve for x?

Mathematics
2 answers:
katrin [286]4 years ago
8 0
The problem equals 360 degrees. So you subtract 221. Then subtract 81 you should be left with X -52 =58. You add 52 to both sides giving you X= 110
inysia [295]4 years ago
7 0
If the angle measure of a circle is 360, then the equation should be:
360=221+81+(x-52)\\
x=110
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Solve the system of equations.<br> ​−2x+15y=−24 <br> ​2x+9y=24 ​​<br> x= y=
german
The answer i think is
x is 12 y is 0

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3 years ago
How many 1 --liter bottles of water does it take to fill a 16-liter jug?
ozzi

Answer:

16

Step-by-step explanation:

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3 years ago
1. The Cajun Heartland State Fair charges $1.25 per ticket for the rides. Johnny bought 25 tickets for the rides and spent a tot
vekshin1

Let number of ride tickets = x tickets and

Total cost of fair admission and ride = $y.

Given cost of each ticket = $1.25 and

Number of tickets = 25 tickets.

Total Cost of 25 ticket  = Number of tickets * cost of each ticket = 25 * 1.25 = $31.25.

Total money spent = $43.75.

Total money spent  =  Fair admission  + Total Cost of 25 ticket

43.75 = Fair addmission + 31.35.

Subtracting 31.25 from both sides, we get

43.75-31.35 = y - 31.35 - 31.35.

12.50 = Fair addmission charge

Therefore, Fair addmission charge = $12.50.

We know slope, intercept form

y = mx+b.

Where, is m the slope (cost of each ticket) and b is the y-intercept( Fair addmission charge)

Plugging values in slope-intercept form, we get

y = 1.25 x+ 12.50.

a) We took x for number of tickets for the rides, and y for total cost of ride tickets and fair admission.

b) We got equation y = 1.25 x+ 12.50.

c) For the equation y = 1.25 x+ 12.50, fix charge for fair admission is $12.50 and cost of each ride ticket is $1.25. Total cost (y) of ride tickets and fair admission will be 1.25 times x number of tickets + $12.50 fair admission charges.


7 0
4 years ago
Determine whether the following propositions are true or false:
Ahat [919]

Answer:

a) false

b) true

c) true

d) true

e) false

Step-by-step explanation:

In a statement of the type:

p ∧ q

where ∧ means "and"

The statement is true only if both p and q are true

the statement is false if p, q, or both, are false.

and in the case of:

p ∨ q

where ∨ means "or"

The statement is true if at least one of p or q (or both) are true.

The statement is false if both are false.

Now that we know that, let's solve the problem:

a) "5 is an odd number and 3 is a negative number."

Here we have:

p = 5 is an odd number

We know that this is true

q = 3 is a negative number

This is false.

then the complete statement is false.

b) "5 is an odd number or 3 is a negative number."

here we have:

p = 5 is an odd number.

this is true

q = 3 is a negative number

because in this case we have an "or", with only p being true, the whole statement is true.

c) "8 is an odd number or 4 is not an odd number."

p = 8 is an odd number  (this is false)

q = 4 is not an odd number  (this is true, 4 is a even number)

Again, we have an "or", so we need only one true proposition, then the statement is true.

d) "6 is an even number and 7 is odd or negative."

p = 6 is an even number  (true)

q = 7 is odd or negative  (notice that we have an or, and 7 is odd is true, so this proposition is true)

Then both propositions are true, then the statement is true.

e) "It is not true that either 7 is an odd number or 8 is an even number (or both)."

This is most complex, this will be true if at least one of the propositions is false.

but:

7 is an odd number is true

8 is an even number is true.

Then both statements are true, which means that the statement is false.

3 0
3 years ago
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