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telo118 [61]
3 years ago
9

George is getting balloons for his father's birthday party. He wants each balloon string to be 6 feet long. At the party store,

string is sold by the yard. If George wants to get 82 balloons, how many yards of string will he need?
Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

Answer:

164 yards

Step-by-step explanation:

Each balloon string = 6 feet

Total balloons needed for the birthday = 82

how many yards of string will he need?

Total strings of balloon needed = Each balloon string × Total balloons needed for the birthday

= 6 feet × 82

= 492 feet

Total strings of balloon needed = 492 feet

1 yard : 3 feet

x yards : 492 feet

1 : 3 = x : 492

1/3 = x / 492

1 * 492 = 3 * x

492 = 3x

x = 492/3

= 164

x = 164 yards

492 feet = 164 yards

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Answer:

\boxed{x=58} & \boxed{m \angle C = 60}

Step-by-step explanation:

You need to find x first in order to find the measure of angle C. To solve for x, we will use the fact that interior angles of a triangle have angle measurements that add up to 180 degrees.

Using this knowledge, we can create an equation where angles A, B, and C add up to equal 180.

  • A+B+C=180
  • (x+4)+(x)+(x+2)=180

Combine like terms on the left side of the equation.

  • 3x + 6 = 180

Subtract 6 from both sides of the equation.

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Divide both sides of the equation by 3.

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Now that you've found the value of x, you can use this value to plug into the expression for angle C.

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Therefore, the final answer is:

x=58\  \text{and} \ m \angle C = 60

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3 years ago
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A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 20 ft from the path and is kept f
krek1111 [17]

Answer:

0.128rad/sec

Step-by-step explanation:

Let x represent the between the man and the point on the path

θ = the angle

dx/dt = 4 ft/s

dθ/dt = rate is the searchlight rotating when the man is 15 ft from the point on the path closest to the searchlight

tan θ = x/20 ft

Cross Multiply

20tan θ = x

dx/dt = 20sec² θ dθ/dt

dθ/dt = 1/20 × cos² θ dx/dt

dθ/dt= 1/20 × cos² θ × 4

dθ/dt = 1/5 × cos² θ

Note : cos θ = 4/5

dθ/dt = 1/5 × (4/5)²

dθ/dt = 16/125

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Relation 1 is a function. Relation 2 is not a function.

Step-by-step explanation:

If the domain is used more than once it is not a function. For example, in Relation 2, -3 was used twice.

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Answer:

Step-by-step explanation:

power raised to power, you multiply the exponents

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For employees at a large company, the mean number of overtime hours worked each week is 9.2 hours with a population standard dev
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Answer:

z=\frac{9.3-9.2}{\frac{1.6}{\sqrt{49}}}= 0.4375

And we can use the normal table and the complement rule we got:

P(z>0.4375)= 1-P(z

Step-by-step explanation:

For this case we have the following parameters given:

\mu = 9.2 , \sigma =1.6

We select a ample size of n=49. And we want to find this probability:

P(\bar X> 9.3)

And for this case is a right tail probability and we can use the z score formula given by:

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And replacing we got:

z=\frac{9.3-9.2}{\frac{1.6}{\sqrt{49}}}= 0.4375

And we can use the normal table and the complement rule we got:

P(z>0.4375)= 1-P(z

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