Answer:
1.44 atm
Explanation:
Step 1:
We'll begin by calculating the number of mole in 2,800,000 Liter of air.
I mole of air occupy 22.4L.
Therefore, Xmol of air will occupy 2800000L i.e
Xmol of air = 2800000/22.4
Xmol of air = 125000 moles
Step 2:
Determination of the pressure when the balloon is fully inflated .
This can be obtained as follow:
Number of mole (n) of air = 125000 moles
Volume (V) = 2800000 L
Temperature (T) = 120°C = 120°C + 273 = 393K
Gas constant (R) = 0.082atm.L/Kmol
Pressure (P) =.?
PV = nRT
Divide both side V
P= nRT/V
P= (125000x0.082x393) / 2800000
P = 1.44 atm
Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm
Answer:
42.3moles
Explanation:
The chemical equation given in this question is as follows:
H2 + O2 → H2O
However, this equation is unbalanced, the balanced chemical equation is as follows:
2H2 + O2 → 2H2O
This equation shows that;
2 moles of hydrogen gas (H2) will produce 2 moles of water (H2O)
Hence, If 42.3 moles of water (H2O) are produced, 42.3 × 2/2
= 42.3moles of hydrogen was reacted.
