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Juliette [100K]
3 years ago
6

748,719.07 compare and contrast the value 7

Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0
Compare: there are 2 other sevens in the number contrast: the sevens are in different place values
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Mr. Sanchez is grading papers. Yesterday he graded 3 papers in 10 minutes. Today, he graded 2 papers in 8 minutes. What was the
siniylev [52]

Answer:

The difference is 3 papers per hour

Step-by-step explanation:

First, you make turn the 10 minutes to 60 minutes by multiplied by 6 and the same to three and you would get 18 paper per hour. Next, you simplify the 8 minute rate to 1 paper in 4 minutes then multiply the 4 by 15 = 60 minutes then the same to the 1 equal to 15 paper per hour. Finally, you subtract 18 - 15 = 3 paper.

3 0
3 years ago
I will give 30 points if u help now
Amiraneli [1.4K]

Answer:

3. x=16

4. x=51

Step-by-step explanation:

3. 3x-8=x+24

2x=32

x=16

4. 2/3(x+27)= 180-(3x-25)

2/3x+18=180-3x+25

11/3x=187

11x=561

x=51

5 0
3 years ago
Read 2 more answers
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).
Dvinal [7]
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:


..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation:  , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
4 0
3 years ago
if triangle ABC is an isosceles triangle and triangle DBE is an equilateral triangle, find each missing measure
BabaBlast [244]

Picture?? This question is incomplete just get a picture then I can answer it



6 0
4 years ago
Which pair of numbers is relatively prime
Anna007 [38]
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).

A.
57=3\cdot19\\&#10;96=2^5\cdot3
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.

143=11\cdot13\\&#10;323=17\cdot19

Indeed, those two numbers are relatively prime.

5 0
3 years ago
Read 2 more answers
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