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miss Akunina [59]
3 years ago
9

Find the values of x and y.

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

x= 45

y= 60

Step-by-step explanation:

For x:

The angles we have are 45 and 90

180°- 45 - 90 = 45

x= 45

For y:

The angles are 30 and 90

180°- 30 - 90 = 60

y= 60

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6 0
3 years ago
Question 12 The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of and
andreev551 [17]

Complete question :

The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.

Answer:

0.10868

Step-by-step explanation:

Given that :

Mean (m) = 3.02

Standard deviation (s) = 0.29

Sample size (n) = 20

Probability of 3.10 GPA or higher

P(x ≥ 3.10)

Applying the relation to obtain the standardized score (Z) :

Z = (x - m) / s /√n

Z = (3.10 - 3.02) / 0.29 / √20

Z = 0.08 / 0.0648459

Z = 1.2336940

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8 0
3 years ago
Becky needs to transfer liquid to a vase using a cylindrical container with a radius of 5 centimeters and a height of 10 centime
Svetradugi [14.3K]

Answer:

Becky needs approximately 3 containers to fil the vase up to 75%.

Step-by-step explanation:

In order to solve this problem we first need to calculate the volume of the container as shown below:

volume = pi*r²*h = pi*5²*10 = 250*pi = 785 cm³

Since becky wants to fill 75% of the vase capacity, she needs to fill:

goal = 2800*75/100 = 2100 cm³

Therefore Becky needs a total of

containers =  goal/volume

containers = 2100/785 = 2.67

Becky needs approximately 3 containers to fil the vase up to 75%.

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3 years ago
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Kazeer [188]

Answer:

11/4+3/6 =13/4or 3 1/4

Step-by-step explanation:

(11*6) + (3*4)

4*6

78/24

78/6=13

24/6=4

13/4 or 3 1/4

13/4=3 1/4

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3 years ago
5.8x10^-1 - 7.4x10^0 in scientific notation.
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5.8 × 10⁻¹ = 0.58

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so

(5.8 × 10⁻¹) - (7.4 × 10⁰) = -6.82 × 10⁰

7 0
2 years ago
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