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tamaranim1 [39]
3 years ago
6

Andrew had a collection of 300 baseball cards at the beginning of the summer After the summer Andrew had traded some of his base

ball cards and know he only has 213 baseball cards What percent is the decrease of his baseball cards collected
Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

The percentage decrease is 29%

Step-by-step explanation:

Given

Initial = 300

Final = 213

Required

Determine the percentage decrease

This is calculated as thus:

\%Percentage = \frac{|Final - Initial |}{Initial} * 100\%

Substitute values for Final and Initial

\%Percentage = \frac{|213 - 300|}{300} * 100\%

\%Percentage = \frac{|-87|}{300} * 100\%

<em>Get absolute value of -87</em>

\%Percentage = \frac{87}{300} * 100\%

\%Percentage = \frac{87* 100\%}{300}

\%Percentage = \frac{8700\%}{300}

\%Percentage = 29\%

Hence, the percentage decrease is 29%

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The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f
Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

h(t)=-16t^{2}+25t+5

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

h(t)=-16(t^{2}-\frac{25}{16}t)+5

Complete the square

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}

Rewrite as perfect squares

h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

The vertex is the point (\frac{25}{32},\frac{945}{64})

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

16(t-\frac{25}{32})^{2}=\frac{945}{64}

(t-\frac{25}{32})^{2}=\frac{945}{1,024}

square root both sides

(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}

t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}

the positive value is

t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec

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1/2 of 2/3 = 1/2 of ____ third(s) =____third(s)
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I'll write the equation again with the blanks filled in.

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3 years ago
Y= -2/3x - 2 2x + y = 2 Find the solution of the systems of linear equation by graphing
egoroff_w [7]
Answer:

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Explanations:

The given system of linear equations is:

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The graph representing the equations is plotted below:

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The point where both lines intersect is the solution to the system of equations.

The lines intersect at the point (3, -4), therefore, (3, -4) is the solution to the system of equations

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