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Afina-wow [57]
2 years ago
8

PLEASE HELP ASAAAAAPPPP

Mathematics
1 answer:
Alex Ar [27]2 years ago
4 0
Equation = y = 9800 * 1.02^x

y = 9800 * 1.02^7 = 11257

 Answer is 2nd choice

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Reflect shape A in the line y = x.
marshall27 [118]

Answer:

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8 0
2 years ago
How can you tell by looking at the coordinates of the two triangles that Δ A'B'C' is a 180° rotation of Δ ABC? A) The coordinate
MariettaO [177]

under a rotation about the origin of 180°

a point (x, y ) → (- x, - y )

hence D is correct, both the x and y coordinates of the points on ΔA'B'C' have opposite signs from the corresponding points on ΔABC


7 0
3 years ago
Read 2 more answers
Can someone give me some 4th grade math problems​
stich3 [128]
1. What is 32×25?

2. What is 856×4?

3. What is 567×40?

Show your work. Sorry if these are too hard.
8 0
3 years ago
Read 2 more answers
Ccalculate the value of f(4) for this function. f(x) = -(x-7)+3 i know the anwser is f(4)=6 but how?
Tasya [4]

Answer:

See below

Step-by-step explanation:

we have f(x) = -(x-7) + 3

and we want to find f(4)

essentially, f(4) means that the input is 4 and to find the output we plug in the value of the input where ever x is and evaluate.

So for f(x) = -(x-7) + 3

To find f(4) we replace all x's with 4

f(4) = -(4-7) + 3

we now evaluate

==> subtract 7 from 4

f(4) = -(-3) + 3

==> apply two negative rule ( basically if there are two negative signs they cancel out and the number turn positive )

f(4) = 3 + 3

==> add 3 and 3

f(4) = 6

5 0
2 years ago
At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
4 0
3 years ago
Read 2 more answers
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