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3 years ago

Guided Practice

Mathematics

1 answer:

sesenic [268]3 years ago

3 0

Answer: A.

quadratic trinomial

I am pretty sure it is letter B

Step-by-step explanation: https://www.softschools.com/math/algebra/topics/classifying_polynomials/

It is either letter A or letter B.. Because

Polynomials can be classified two different ways - by the number of terms and by their degree.

1. Number of terms.

A monomial has just one term. For example, 4x2 .Remember that a term contains both the variable(s) and its coefficient (the number in front of it.) So the is just one term.

A binomial has two terms. For example: 5x2 -4x

A trinomial has three terms. For example: 3y2+5y-2

Any polynomial with four or more terms is just called a polynomial. For example: 2y5+ 7y3- 5y2+9y-2

Practice classifying these polynomials by the number of terms:

1. 5y

2. 3x2-3x+1

3. 5y-10

4. 8xy

5. 3x4+x2-5x+9

Answers: 1) Monomial 2) Trinomial 3) Binomial 4) Monomial 5) Polynomial

2. Degree. The degree of the polynomial is found by looking at the term with the highest exponent on its variable(s).

Examples:

5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial.

3x4+4x2The highest exponent is the 4 so this is a 4th degree binomial.

8x-1 While it appears there is no exponent, the x has an understood exponent of 1; therefore, this is a 1st degree binomial.

5 There is no variable at all. Therefore, this is a 0 degree monomial. It is 0 degree because x0=1. So technically, 5 could be written as 5x0.

3x2y5 Since both variables are part of the same term, we must add their exponents together to determine the degree. 2+5=7 so this is a 7th degree monomial.

Classify these polynomials by their degree.

1.7x3+52+1

2.6y5+9y2-3y+8

3.8x-4

4.9x2y+3

5.12x2

Answers 1) 3rd degree 2) 5th degree 3) 1st degree 4) 3rd degree 5) 2nd degree

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When Liz woke up in the morning, it was 6°F. By the late afternoon, the temperature had dropped 9°F.

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Given:

Temperature in the morning = 6°F.

By the late afternoon, the temperature had dropped 9°F.

To find:

The temperature by the late afternoon.

Solution:

Temperature by the late afternoon = Morning temperature - Dropped temperature

Using the given values and the above formula, we get

Temperature by the late afternoon = 6°F - 9°F

Temperature by the late afternoon = -3°F

Therefore, the temperature by the late afternoon is -3°F.

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3 years ago

Emily Dickinson's poetry was rescued for posterity by

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3 years ago

Write the equation of the line shown in point-slope form. (2,1) (3,8)

Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

$\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}$

${(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)$ ..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

$(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)$

$(y -8) = \frac{(- 7)}{(-1)}(x-3)$

y – 8 = 7(x – 3)

y – 8 = 7x – 21

7x – y = 21 – 8

7x – y = 13

Hence, the line equation that passes through the given points is 7x – y = 13

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4 years ago

Plz help, really would appreciate it!!! =]

Nonamiya [84]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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