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marin [14]
3 years ago
6

A factory produce bicycles at a rate of 110+0.5t^2-0.9t bicycles per week (t in weeks)

Mathematics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

We need to integrate the function with the limits of 1 to 3.

\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt

\int_{1}^{3} (110 + \dfrac{t^2}{2} - \dfrac{9t}{10}) dt

= 110t + \dfrac{t^3}{6} - \dfrac{9t^2}{20} \Biggr|_{1}^{3}

= 330.45 - 109.72

= 220.7333

Answer: 221

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Ajax is 5 and 1 fourth feet tall. His sister is 3 eighths foot shorter than Ajax How tall is Ajax Sister?
user100 [1]

Answer:

4\frac{3}{4} feet tall

Step-by-step explanation:

Ajax is "5 and 1 fourth feet tall", which can be written as the mixed number 5\frac{1}{4} .

His sister is "3 eighths foot shorter", so she's 3/8 feet shorter than 5 1/4.

So, this is just a subtraction problem:

5\frac{1}{4} -\frac{3}{8}

To solve this, we want to convert 5 1/4 into an improper fraction, which is: \frac{21}{4} . Now, we want to find a common denominator. In this case, that common denominator is 8, so \frac{21}{4} =\frac{42}{8} .

Finally, we subtract 3/8 from 42/8: \frac{42}{8} -\frac{3}{8} =\frac{39}{8} . So, Ajax's sister is 39/8 feet. Converting this into a mixed number, we have: 39/8 = 4\frac{6}{8} =4\frac{3}{4} .

Therefore, Ajax's sister is 4\frac{3}{4} feet tall.

Hope this helps!

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3 years ago
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What is the equation of this line in slope-intercept form?<br> (-1,5) (1,-1)
enot [183]

Answer:

y=-3x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-5)/(1-(-1))

m=-6/(1+1)

m=-6/2

m=-3

y-y1=m(x-x1)

y-5=-3(x-(-1))

y-5=-3(x+1)

y=-3(x+1)+5

y=-3x-3+5

y=-3x+2

4 0
2 years ago
Eth enlarged the triangle below by a scale of 5.
levacccp [35]

Answer:

She should have multiplied one half (4)(3.5) by 5 squared.

Step-by-step explanation:

We are given that

Base of triangle=b=4 cm

Height of triangle=h=3.5 cm

Area of triangle=\frac{1}{2}bh=\frac{1}{2}(4)(3.5) cm^2

After enlarged

Scale factor=5

New base of enlarged triangle=b'=4(5) cm

Height of enlarged triangle=h'=3.5(5) cm

Area of enlarged triangle=\frac{1}{2}4(5)(3.5\times 5)=\frac{1}{2}(4)(3.5)(5^2) cm^2

But Beth wrote

Area of enlarged triangle=\frac{1}{2}(4)(3.5)(5)=35 cm^2

She should have multiplied one half (4)(3.5) by 5 squared.

3 0
3 years ago
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Where is
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