Question

A factory produce bicycles at a rate of 110+0.5t^2-0.9t bicycles per week (t in weeks)

Answer 1

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

We need to integrate the function with the limits of 1 to 3.

$\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt$

$\int_{1}^{3} (110 + \dfrac{t^2}{2} - \dfrac{9t}{10}) dt$

$= 110t + \dfrac{t^3}{6} - \dfrac{9t^2}{20} \Biggr|_{1}^{3}$

$= 330.45 - 109.72$

$= 220.7333$

Answer: 221