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zhuklara [117]
2 years ago
13

Consider the equations below:

Mathematics
1 answer:
garik1379 [7]2 years ago
5 0

Answer:

D

Step-by-step explanation:

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Solve the following equation q=1/3bh , for b
xz_007 [3.2K]

b=3q/8 or at least thats what I got

7 0
3 years ago
Pls answer and let me know if i can factor this r not
enyata [817]

Answer:

18r-4

Step-by-step explanation:

Here is your anwer

6 0
2 years ago
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Michael is 4 years younger than twice his cousin, Damien’s age. The sum of their ages is 46. How old is Damien?
Verizon [17]
Let x = The age of Michael
Let 2x-3 = The age of Michaels cousin
X+2x-3=46
x=16+1/3
X = 49 years

I think that’s the answer I’m not 100% sure though
4 0
3 years ago
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
Find each measure <br><br> Please help me
Crazy boy [7]

Answer:

see explanation

Step-by-step explanation:

∠ YXW = ∠ ZXV ( vertically opposite angles ) , so

4a + 15 = 2a + 65 ( subtract 2a from both sides )

2a + 15 = 65 ( subtract 15 from both sides )

2a = 50 ( divide both sides by 2 )

a = 25

Then

(7)

∠ ZXV = 2a + 65 = 2(25) + 65 = 50 + 65 = 115°

(8)

∠ YXW = ∠ ZXV = 115°

∠ ZXY and ∠ ZXV are adjacent angles and sum to 180° , that is

(9)

∠ ZXY = 180° - 115° = 65°

(10)

∠ VXW = ∠ ZXY = 65° ( vertically opposite angles

8 0
3 years ago
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