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Lesechka [4]
3 years ago
11

Sandra left home with $200 in her wallet. Sandra spent 25% of her money on

Mathematics
1 answer:
Elena L [17]3 years ago
5 0

Answer:

$30

Step-by-step explanation:

shoes: 25/100(200)=

1/4(200)=50

she spent $50 on shoes

clothes: 3/5(200)=

she spent $120 on clothes

50+120=170

200-170=30

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Please help me if you know, thank you!!
Oduvanchick [21]
GG easy
I=(r)(t)(P)P=principalr=rate in decimalt=timei=interest
so just plug in what you know to solve for what you don't know
first oneI=(0.05)(3)(100)
I=15

2nd one20=(0.04)(t)(500)20=20tdivide by 20 both sides1=tt=1
3rd one35=(0.10)(7)(P)35=0.70Pdivide both sides by 3550=PP=50

4th one6=(r)(2)(200)
6=400rdivide both sides by 4000.015=rconvert to percent1.5%=r
4 0
3 years ago
Help. I will be guessing on this, but I want to make sure this is on here so no one has to guess like I am. Help a brother out
GaryK [48]

Answer:

Line 3

Step-by-step explanation:

→ Calculate gradient

\frac{6-3}{4-2} =1.5

7 0
3 years ago
Read 2 more answers
A system of equations is graphed on a
Ira Lisetskai [31]

Answer:

(1, 4)  

Step-by-step explanation:

\text{It looks as if "they" are asking you to solve the problem graphically.}\\\text{Then, you must solve each equation for y, plot a few points for each graph,}\\ \text{and see where each graph intersects. }

\begin{array}{rcl}(1) & 2x + 3y = 12 & \\& 3y = 12 - 2x& \text{Subtracted 2x from each side}\\ & y = 4 - \dfrac{2}{3}x & \text{Divided each side by3}\\\\(2) & 4x + 2y =10& \\& 2y = 10 - 4x& \text{Subtracted 2x from each side}\\ & y = 5 - 2x & \text{Divided each side by 2}\\\end{array}\\

Below are a few points for Equations (1) and (2).}

\begin{array}{cc|cc}\mathbf{x} & \mathbf{y} & \mathbf{x} & \mathbf{y}\\0 & 4 & 0 & 5\\& & 1 & 3\\& & 2 & 1\\3 & 2 & &\\6 & 0 & &\\\end{array}\\

Equation (1) is the blue line in the graph below.

Equation (2) is the red line.

The two lines cross at the black dot

Your four points are labelled . The one that is closest to the intersection is (1, 4).

The approximate solution to the system of equations is (1, 4).

8 0
2 years ago
Consider this expression.(The square root of a to the power of 3 - 7 )+ lbl When a = 2 and b = -4, the value of the expression i
lesya692 [45]

Given that: a = 2, b = -4

\sqrt{a^3-7}\text{ + |b| = }\sqrt{2^3-7}\text{ + |-4| = }\sqrt{8-7}\text{ }+\text{ 4 = }\sqrt{1}+\text{ 4 = 1 + 4 = 5}

3 0
11 months ago
If c(x)= 5/x-2 and d(x) = x + 3, what is the domain of (cd)(x)?
Nataly [62]

(fg)(x)=f(x)\cdot g(x)\\\\\text{We have}\ c(x)=\dfrac{5}{x-2}\ \text{and}\ d(x)=x+3.\ \text{Substitute}\\\\(cd)(x)=\dfrac{5}{x-2}\cdot(x+3)=\dfrac{5(x+3)}{x-2}\\\\\text{Domain:}\\\\\text{The denominator must be different than zero. Therefore}\\\\x-2\neq0\to x\neq2\\\\Answer:\ \text{Domain is the set of all real numbers except 2}\to D=\mathbb{R}-\{2\}

3 0
3 years ago
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