Answer:
troupe ta reponse too meme je ne confused pas mais churches tu va trouver ou tu voie les autres responses correct
Well for starters that would be $108/6 weeks when a unit rate is anything over one. To put it as a unit rate (how many dollars per hours) you just divide $108 by 6 (since you would divide 6 by 6 to get) and the unit rate would end up being $18 per hour.
Answer:
1. Use a compass to make arc marks which intersect above and below then connect.
2. ![y=\frac{1}{3}x + 2](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx%20%2B%202)
Step-by-step explanation:
1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.
2. The point slope form of a line is
where
. We write
Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.
Simplify for slope intercept form.
![(y-1)=\frac{1}{3}(x+3)\\(y-1)=\frac{1}{3}x+1\\y=\frac{1}{3}x + 2](https://tex.z-dn.net/?f=%28y-1%29%3D%5Cfrac%7B1%7D%7B3%7D%28x%2B3%29%5C%5C%28y-1%29%3D%5Cfrac%7B1%7D%7B3%7Dx%2B1%5C%5Cy%3D%5Cfrac%7B1%7D%7B3%7Dx%20%2B%202)
Answer:
12. 9
Step-by-step explanation:
12. Using Pythagoras theorem
let shortest distance be = x
8 square + 5 square = x square
64 + 25 = x square
89 = x square
Therefore x = square root of 89
Thus X = 9
Answer:
Radius=2.09 cm
Height,h=14.57 cm
Step-by-step explanation:
We are given that
Volume of cylinderical shaped can=200 cubic cm.
Cost of sides of can=0.02 cents per square cm
Cost of top and bottom of the can =0.07 cents per square cm
Curved surface area of cylinder=![2\pi rh](https://tex.z-dn.net/?f=2%5Cpi%20rh)
Area of circular base=Area of circular top=![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
Total cost,C(r)=![0.02\times 2\pi rh+2\pi r^2\times 0.07](https://tex.z-dn.net/?f=0.02%5Ctimes%202%5Cpi%20rh%2B2%5Cpi%20r%5E2%5Ctimes%200.07)
Volume of cylinder,![V=\pi r^2 h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E2%20h)
![200=\pi r^2 h](https://tex.z-dn.net/?f=200%3D%5Cpi%20r%5E2%20h)
![h=\frac{200}{\pi r^2}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B200%7D%7B%5Cpi%20r%5E2%7D)
Substitute the value of h
![C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07](https://tex.z-dn.net/?f=C%28r%29%3D0.02%5Ctimes%202%5Cpi%20r%5Ctimes%20%5Cfrac%7B200%7D%7B%5Cpi%20r%5E2%7D%2B2%5Cpi%20r%5E2%5Ctimes%200.07)
![C(r)=\frac{8}{r}+0.14\pi r^2](https://tex.z-dn.net/?f=C%28r%29%3D%5Cfrac%7B8%7D%7Br%7D%2B0.14%5Cpi%20r%5E2)
Differentiate w.r.t r
![C'(r)=-\frac{8}{r^2}+0.28\pi r](https://tex.z-dn.net/?f=C%27%28r%29%3D-%5Cfrac%7B8%7D%7Br%5E2%7D%2B0.28%5Cpi%20r)
![C'(r)=0](https://tex.z-dn.net/?f=C%27%28r%29%3D0)
![-\frac{8}{r^2}+0.28\pi r=0](https://tex.z-dn.net/?f=-%5Cfrac%7B8%7D%7Br%5E2%7D%2B0.28%5Cpi%20r%3D0)
![0.28\pi r=\frac{8}{r^2}](https://tex.z-dn.net/?f=0.28%5Cpi%20r%3D%5Cfrac%7B8%7D%7Br%5E2%7D)
![r^3=\frac{8}{0.28\pi}=9.095](https://tex.z-dn.net/?f=r%5E3%3D%5Cfrac%7B8%7D%7B0.28%5Cpi%7D%3D9.095)
![r=(9.095)^{\frac{1}{3}}=2.09](https://tex.z-dn.net/?f=r%3D%289.095%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D2.09)
Again, differentiate w.r.t r
![C''(r)=\frac{16}{r^3}+0.28\pi](https://tex.z-dn.net/?f=C%27%27%28r%29%3D%5Cfrac%7B16%7D%7Br%5E3%7D%2B0.28%5Cpi)
Substitute the value of r
![C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0](https://tex.z-dn.net/?f=C%27%27%282.09%29%3D%5Cfrac%7B16%7D%7B%282.09%29%5E3%7D%2B0.28%5Cpi%3D2.63%3E0)
Therefore,the product cost is minimum at r=2.09
h=![\frac{200}{\pi (2.09)^2}=14.57](https://tex.z-dn.net/?f=%5Cfrac%7B200%7D%7B%5Cpi%20%282.09%29%5E2%7D%3D14.57)
Radius of can,r=2.09 cm
Height of cone,h=14.57 cm