Given pair of lines are x² + 4xy + y² = 0
⇒ (y/x) ² + 4 y/x + 1 = 0
⇒ y/x = -4±2√3/2 = -2±√3,
∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle
Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,
The perpendicular distance form origin to x - y = 4 is the height of the
h = 2 √ 2
∵ Area of triangle = h²/√3 = 8/√3
Answer:
Step-by-step explanation:
a= adult ticket
a= student ticket
5a+1s=2874
1a+1s=1246
Subtract the second equation from the first one
4a=1628
a=407
a+s=1246
407+s=1246
s=839
Answer:
It intersects the x-axis at x = 10
Step-by-step explanation:
Step 1: Find slope <em>m</em>
m = (5 - 1)/(5 - 9)
m = 4/-4
m = -1
y = -x + b
Step 2: Find <em>b</em>
5 = -5 + b
b = 10
Step 3: Rewrite equation
y = -x + 10
Step 4: Find <em>x</em> when <em>y</em> = 0
0 = -x + 10
-10 = -x
x = 10
So the graph crosses the x-axis at 10.
Answer:
d < 1
Step-by-step explanation:
First, we have to get d on the same side of the equation. So we will subtract d from both sides and the equation will be 12d-d < + 11. We could also write this problem as d(12-1) < 11, which when simplified would be d(11) < 11. Next, divide both sides by 11 and you get d< 1. Hope this helps and have a great day!!:D
Answer:
The slope would would be -2
Step-by-step explanation:
