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Verizon [17]
3 years ago
9

What is the value of x?

Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0

Answer:

8√2

Step-by-step explanation:

The 45-45-90 triangle theorem states that the two congruent sides of an isoceles right triangle are the same, and the hypotenuse of the triangle is √2 times more than the common side. So, if the common side is 8, then the hypotenuse is 8√2.

ElenaW [278]3 years ago
3 0

Answer:

C) 8\sqrt{2}

Step-by-step explanation:

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Help me fast asap this is due by the end of class
Rufina [12.5K]

Answer:

D

Step-by-step explanation:

-12/6= -2

x^10/x^8= x^2

y^3/y= y^2

5 0
2 years ago
Can you help me get the answer for <br> 1/3+1/4<br> plz
Ivahew [28]
7/12 is the answer :)
6 0
2 years ago
Read 2 more answers
Solve 4/x-4=x/x-4-4/3 for x and determine if the solution is extraneous or not
4vir4ik [10]

<u>Answer:</u>

x = 4 (extraneous solution)

<u>Step-by-step explanation:</u>

\frac { 4 } { x - 4 } = \frac { x } { x - 4 } - \frac { 4 } { 3 } \\ \frac { 4 } { x - 4 } - \frac { x } { x - 4 } = - \frac { 4 } { 3 } \\ \frac { 4 - x } { x - 4 } = - \frac { 4 } { 3 } \\ 3 ( 4 - x ) = - 4 ( x - 4 ) \\ 1 2 - 3 x = - 4 x + 1 6 \\ 4 x - 3 x = 1 6 - 1 2 \\ x = 4 \\

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back x=4, we will get two fractions with zero denominator which would be undefined.

7 0
3 years ago
in each of the following divide the second number by the first number and find the quotient:3/4,-3/8​
madam [21]

Answer:

-3

Step-by-step explanation:

-3/8÷3/4

=-3/8×4/3

=-6/2

=-3

5 0
3 years ago
he data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower clas
Licemer1 [7]

Answer:

It is not normally distributed as it has it main concentration in only one side.

Step-by-step explanation:

So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).

So, let us begin the groupings into their different classes, shall we?

Data given:

0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.

(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.

(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31

(3). 0.4 - 0.6 : there are 2 values that falls into this category.

(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.

Class interval            frequency.

0.00 - 0.20.                   15.

0.20 - 0.40.                    2.

0.4 - 0.6.                        2.

4 0
3 years ago
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