Solve this. Please and thank you.
1 answer:
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We have that
<span>f(x)=3x
g(x)=x</span>²<span>+5
</span>g(x)/f(x)=[x²+5]/[3x]
<span>that new function will exist for all real numbers except the value of zero, value for which it becomes indefinite
</span>
the domain is the interval (-∞,0) U (0,∞)
using a graph tool
see the attached figure
<span>f(x)=3x
g(x)=x</span>²<span>+5
</span>g(x)/f(x)=[x²+5]/[3x]
<span>that new function will exist for all real numbers except the value of zero, value for which it becomes indefinite
</span>
the domain is the interval (-∞,0) U (0,∞)
using a graph tool
see the attached figure
<span>y - 1 = 2 (x - 2) is the red graph.
</span><span>4x + 6y = -12 is the blue graph.
</span><span>f (x) = -</span>
<span>x - 2 is the green graph.
:)</span>
</span><span>4x + 6y = -12 is the blue graph.
</span><span>f (x) = -</span>
:)</span>
Answer:
The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.
This means that
What proportion of childrenin this age range between 70 lbs and 85 lbs.
This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So
X = 85
has a pvalue of 1
X = 70
has a pvalue of 0.0694
1 - 0.0694 = 0.9306
The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.