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Debora [2.8K]
3 years ago
14

Me and my friend were checking answers, but then our answers differed on one question by one digit. The question is: [(21-13)+(3

2-24)]×4
Mathematics
2 answers:
Yanka [14]3 years ago
8 0

[(21-13)+(32-24)]x4

[8+8]4

16x4

64

That’s what I got

Sunny_sXe [5.5K]3 years ago
5 0

[(21-13)+(32-24)] x 4

[(8)+(8)] x 4

16 x 4

= 64

If this helped you, please list me as brainliest!

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Find the Value of x. Someone Help me please for Questions 6 through 9. Ill give Points. :)
PSYCHO15rus [73]

Answer:

6. X= 121

7. x= 18

8. X= 7

9. x= 31

Step-by-step explanation: do u need the steps?

8 0
2 years ago
Many employees screen gpa in addition to a variety of skills. Suppose a student is in the last semester of college and has a 2.6
wel

Answer:

  • Overall GPA=2.81
  • It is not possible to get his GPA to 3.0 for graduation.

Step-by-step explanation:

The Student already has a GPA of 2.68 after 108 credit hours.

If he is taking 12 credit hours in his last semester and gets a perfect 4.0 GPA

Total Credits Earned Before = 2.68 X 108=2894.4

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Total credit Hour= 108+12=120 Hours

His Cumulative GPA = Total credits earned ÷ Total Credit Hour

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Since 2.81 is less than 3.00, it is not possible to get his GPA to 3.0 for graduation.

3 0
4 years ago
A TV company when purchasing thousands electronic components apply this sampling plan: randomly select 15 of them and then accep
katrin [286]
<h2>Answer with explanation:</h2>

According to the Binomial probability distribution ,

Let x be the binomial variable .

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P(X=x)=^nC_xp^x(1-p)^{n-x} , where n is the total number of trials or the sample size and p is the probability of getting success in each trial.

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n = 15

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Probability of getting defective components = P = 0.03

The whole batch can be accepted if there are at most two defective components. .

The probability that the whole lot is accepted :

P(X\leq 2)=P(x=0)+P(x=1)+P(x=2)\\\\=^{15}C_0(0.03)^0(0.97)^{15}+^{15}C_1(0.03)^1(0.97)^{14}+^{15}C_2(0.03)^2(0.97)^{13}\\\\=(0.97)^{15}+(15)(0.03)^1(0.97)^{14}+\dfrac{15!}{2!13!}(0.03)^2(0.97)^{13}\\\\\approx0.63325+0.29378+0.06360=0.99063

∴The probability that the whole lot is accepted = 0.99063

For sample size n= 2500

Expected value : \mu=np= (2500)(0.03)=75

The expected value = 75

Standard deviation :  \sigma=\sqrt{np(1-p)}=\sqrt{2500(0.03)(0.97)}\approx8.53

The standard deviation = 8.53

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3 years ago
State if the pair of triangles are similar. If so, state how you know they are similar and
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