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2 years ago

6

If arc lm = 20 ft, find the radius of N

2 answers:

lozanna [386]2 years ago

5 0

Answer:

120 ft

Step-by-step explanation:

60/360 or 1/6 of circle = 20 ft

full circle = 20 x 6 = 120 ft

diameter = 120/3.14 = 38.22 ft

radius = 38.22/2 = 19.11 ft

kirza4 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

60° = ⅙ of 360°, so length of arc LM = ⅙ of 2πr.

20 = 2πr/6

r = 60/π ft

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Which of the diagrams below represents the contrapositive of the statement "If it is an elm, then it is a tree"?

Murrr4er [49]

Answer:

Right

Step-by-step explanation:

For a contrapositive, we switch the hypothesis and conclusion and then negate it.

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2 years ago

Provide an appropriate response.

aivan3 [116]

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1 year ago

Please solve and graph each inequality x-7<-12

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2 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

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$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

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Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

2 years ago

Read 2 more answers

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sp2606 [1]

Answer:

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