A segment is bounded by two endpoints.
The two segments can have up to two common points
Assume the line segments are AB and CD where the length of AB is greater than the length of CD.
<u>The possibilities are:</u>
- <em>A point of segment CD lies on segment AB</em>
- <em>Both points of segment CD lie on segment AB.</em>
<em />
See attachment for both possibilities.
Hence, it is possible for the two segments to have two common points.
Read more about line segments at:
brainly.com/question/18983323
The two tangent lines for each circle are the same length. Set the equations to equal and solve for x.
1. 4x + 3 = 3x +12
Subtract 3x from each side:
x +3 = 12
Subtract 3 from both sides:
x = 9
2. -2 + x = 2x -7
Subtract 2x from both sides:
-2 - x = -7
Add 2 to each side:
-x = -5
Multiply both sides by -1:
x = 5
Answer:
$8.50
Step-by-step explanation:
I don't know what Alls are, but if Carlos insists, we can calculate how much he can spend on Alls with the expression:
($31.50) + r
$40
This says the sum of what Carlos has already spent (hot dogs and hamburgers) plus the amount he spends on Alls (rolls?), r, must be equal to or less than the $40 he has allowed himself to spend.
($31.50) + r
$40
r
$40 - $31.50
r
$8.50
Answer:
digits are: 0, 4, 8. The required number is: 480.
Step-by-step explanation:
→ Let ones digits is 'x', then according to the condition the hundreds digit is 'x+4', and the tens digit is '2(x+4)'.
→ According to the condition the sum of the digits is: x+(x+4)+2(x+4)=12.
→ After evaluation this equation, x=0 - this is ones digit;
→ x+4=0+4=4 - this is hundreds digit;
→ 2(x+4)=2(0+4)=8 - this is ten digit.