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Iteru [2.4K]
1 year ago
13

Hello I need help with question 12! I will give you a great rating! Please help, I’m not sure how to do this. Also this is not a

quiz this is practice

Mathematics
1 answer:
Shkiper50 [21]1 year ago
4 0

Given the following question:

Lable all the sides of the triangle:

Hypotenuse is the missing side

Right angle is the opposite

Adjacent is equal to 21

We have all of our sides so now we won't get them mixed up when finding the missing value of this triangle.

sin =

opp/hyp

cos =

adj/hyp

tan =

opp/adj

Since we are given the adjacent side and we are trying to find the hypotenuse we will solve for cos since we have the adjacent side but we need the hypotenuse

cos(35)=21/x

Now solve:

\begin{gathered} cos35^{\circ}=\frac{21}{x} \\ x\times x=0 \\ (x)cos35=21 \\ \frac{cos35}{cos35}=0 \\ \frac{21}{cos35}=25.6362664 \\ 25.6362664 \\ 3

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This graph represents a quadratic function. What is the function's equation written in factored form and in vertex form?
grigory [225]

Answer:

vertex form:  f (x) = 2 * (x - 2) ^ 2 - 8

factored form: f (x) = 2 * x * (x - 4)

Step-by-step explanation:

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f (x) = a * (x - h) ^ 2 + k

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The vertex is the point (2, -8), we replace and we are left with:

f (x) = a * (x - 2) ^ 2 - 8

Now, to calculate the value of the coefficient we are going to

mark a point on the graph

, we will select (0,0)

and replacing we have:

0 = a * (0 - 2) ^ 2 - 8

0 = 4 * a - 8

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a = 2

Therefore, we would be left with the equation of the function written in The first thing is to calculate the equation with its vertex form, we can calculate it knowing that it is formulated in the following:

f (x) = a * (x - h) ^ 2 + k

where

a is a coefficient

(h, k) is the vertex

Looking at the graph

The vertex is the point (2, -8), we replace and we are left with:

f (x) = a * (x - 2) ^ 2 - 8

Now, to calculate the value of the coefficient we are going to

mark a point on the graph

, we will select (0,0)

and replacing we have:

0 = a * (0 - 2) ^ 2 - 8

0 = 4 * a - 8

a = 8/4

a = 2

Therefore, we would be left with the equation of the function written in vertex form:

f (x) = 2 * (x - 2) ^ 2 - 8

Now for the factored form, we know it has the following structure:

f (x) = a * (x - x1) * (x - x2)

knowing that a is a coefficient

and that x1 and x2 are the zeros or x-intercepts of the function

Looking at the graph

The zeros or x-intercepts of the function are

x = 0 and x = 4

so

f (x) = a * (x - 0) * (x - 4)

f (x) = a * x * (x - 4)

To calculate the value of the coefficient a, we will take the point (2, -8), we replace:

-8 = a * 2 * (2 - 4)

-8 = 4 * a - 8 * a

4 * a = 8

a = 2

we replace and we have:

f (x) = 2 * x * (x - 4) and this would be the factored form of the equation

Now for the factored form, we know it has the following structure:

f (x) = a * (x - x1) * (x - x2)

knowing that a is a coefficient

and that x1 and x2 are the zeros or x-intercepts of the function

Looking at the graph

The zeros or x-intercepts of the function are

x = 0 and x = 4

so

f (x) = a * (x - 0) * (x - 4)

f (x) = a * x * (x - 4)

To calculate the value of the coefficient a, we will take the point (2, -8), we replace:

-8 = a * 2 * (2 - 4)

-8 = 4 * a - 8 * a

4 * a = 8

a = 2

we replace and we have:

f (x) = 2 * x * (x - 4) and this would be the factored form of the equation

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