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KATRIN_1 [288]
3 years ago
11

Can someone please help me with this ?

Mathematics
1 answer:
Lemur [1.5K]3 years ago
4 0
I believe the area is 704

the area of the square is 484
the area of the triangle is 220
484+220=704
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Sea level is the average level of the sea between high and low tide. It is used as a reference point for measuring elevation, or
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735

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3 years ago
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X² + 2x²-3x-6<br><br> Get the zeros
kati45 [8]
Write the polynomial as an equation.
y
=
x
3
−
2
x
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x
3
-
2
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0
and solve.
0
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x
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−
2
x
2
−
3
x
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6
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x
3
-
2
x
2
-
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The result can be shown in multiple forms.
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x
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√
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√
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x
=
2
,
3
,
-
3
Decimal Form:
x
=
2
,
1.73205080
…
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−
1.73205080
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8 0
4 years ago
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F = {(-3, -4),(-1,5), (3,1),(2, -4)}<br> What’s the domain
solong [7]

Answer:

Step-by-step explanation:

the domain is : A = {-3, -1, 3, 2}

8 0
3 years ago
Can someone help me out with some pesky math quiz :) I put a pic
Sindrei [870]

1. Simplifying ∛54 gives 3∛2

2. 27^1/3 * (27)^3 is equal to  27

3. The expression (2j4k)^4/5 can be written as \sqrt[4]{32j^{20}k^{5}  }^{5} making the first option the correct option

4. simplifying \sqrt[4]{16x^{4} y^{12} } will result to 2x∛y

5. simplifying \sqrt[5]{2940x^{13} y^{7} } will result to 14x^{6} y^{3} \sqrt{15xy} making the last option the correct option

<h3>How to simplify \sqrt[5]{2940x^{13} y^{7} }</h3>

<u>given data</u>

\sqrt[5]{2940x^{13} y^{7} }

= ( 2940 * x^13 * y^7 )^1/5

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}

multiplying the values inside the parenthesis by ^1/2

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2}  * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15xy)^{1/2}

= ( 14x^6y^3 ) \sqrt{( 15xy)}

we can therefore say that the last option is the answer

Read more on equations here: brainly.com/question/22688504

#SPJ1

3 0
1 year ago
8.4.49 A cow is tethered to one corner of a square​ barn, 19 feet by 19 ​feet, with a rope 160 feet long.​ (See the illustration
SashulF [63]

Answer:

20096 ft^2

Step-by-step explanation:

We are given that

Length of rope=l=160 feet

Radius of quadrant of circle=r=160 feet

We have to find the  maximum grazing area of the cow.

We know that

Area of quadrant of circle=\frac{1}{4}\pi r^2

Where \pi=3.14

Using the formula

Area grazed by cow=\frac{1}{4}\times 3.14(160)^2

Area grazed by cow=20096 ft^2

4 0
4 years ago
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