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3 years ago

Solve |y + 2| > 6 pls help

Mathematics

1 answer:

solmaris [256]3 years ago

7 0

Answer:

Step-by-step explanation:

Definition of an absolute value is:

$|a|=\left \{ {{a, if a\geq 0} \atop {-a, if a$

1). Assume that (y + 2) ≥ 0, then

y + 2 > 6 ⇒ y > 4

2). Now, if (y + 2) < 0, then

- (y + 2) > 6 ⇔ - y - 2 > 6 ⇒ y < - 8

y ∈ ( - ∞ , - 8) ∪ (4 , ∞ )

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3/4 divided by 1/2 plz help asap

lora16 [44]

Dividing by a fraction is the same as multiplying by the reciprocal. so dividing by 1/2 is the same as multiplying by 2/1, or 2. so (3/4)/(1/2) = (3/4)*2 = 6/4 = 1 and 1/2

5 0

3 years ago

Please help a) B) C)

fomenos

I'm pretty sure it should be B)

6 0

4 years ago

Consider this population data set:4, 6, 7, 11, 12, 18, 26, 23, 14, 31, 22, and 12. The values 11, 31, 22, and 12 constitute a ra

irga5000 [103]

Answer:

3.5

Step-by-step explanation:

Find the Mean of the Population Data Set

4 + 6 + 7 + 11 + 12 + 18 + 26 + 23 + 14 + 31 + 22 + 12 = 186

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Subtract

19 - 15.5 = 3.5

Answer: The sample mean is more than the population mean by 3.5

3 0

3 years ago

A map distance of 5 inches represents 200 miles of actual distance. Suppose the distance between two cities on the map is 7 inch

puteri [66]

The actual distance is 280. To find the answer you find the unit rate which is 1/40 (1 inch for 40 miles) then multiply the given number (7) by the unit rate (40).

6 0

4 years ago

Mark's school is selling tickets to the annual dance competition. On the first day of ticket sales the school sold 4 senior tick

erica [24]

The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

Solution:

Let "a" be the price of each senior ticket

Let "b" be the price of each child ticket

On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68

Thus a equation is framed as:

4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68

$4 \times a + 4 \times b = 68$

4a + 4b = 68 ---------- eqn 1

The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets

Similarly, we frame a equation as:

$12 \times a + 5 \times b = 120$

12a + 5b = 120 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

12a + 12b = 204 -------- eqn 3

Subtract eqn 2 from eqn 3

12a + 12b = 204

12a + 5b = 120

( - ) --------------

7b = 84

b = 12

Substitute b = 12 in eqn 1

4a + 4(12) = 68

4a + 48 = 68

4a = 20

a = 5

Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

4 0

3 years ago