Solve |y + 2| > 6 pls help

Mathematics

1 answer:

solmaris [256]2 years ago

7 0

Answer:

Step-by-step explanation:

Definition of an absolute value is:

$|a|=\left \{ {{a, if a\geq 0} \atop {-a, if a$

1). Assume that (y + 2) ≥ 0, then

y + 2 > 6 ⇒ y > 4

2). Now, if (y + 2) < 0, then

- (y + 2) > 6 ⇔ - y - 2 > 6 ⇒ y < - 8

y ∈ ( - ∞ , - 8) ∪ (4 , ∞ )

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