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2 years ago

BRAINLIEST (9th grade mathematics)

Mathematics

2 answers:

qwelly [4]2 years ago

7 0

The answer to the question is 10

liraira [26]2 years ago

6 0

Answer:

5 m/min

Step-by-step explanation:

Initial speed = 6 m/ min

Final speedd = 4 m/ min

$Average\:speed\:=\:\dfrac{total\:speed}{2}$

Average speed = $\dfrac{ 6 + 4}{2}$

Avg. Speed = 5 m / min.

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Juan's pit crew was able to get his car back onto the racetrack 0.4 seconds faster than Paul's crew. Paul's crew took 1.3 second

9966 [12]

Answer:

6.7 seconds

Step-by-step explanation:

Juan= Paul-0.4

Paul=Terry+1.3

We can substitute Terry+1.3 for Paul since they are equal

juan=(Terry-0.4)+1.3

terry=5.8

juan=(5.8-0.4)+1.3

juan=6.7

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3 years ago

Write the slope intercept form of the equation of each line

Advocard [28]

Answer:

y = -1/3

Step-by-step explanation:

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2 years ago

Melissa has more than 40 coins in her collection which inequality the nuber of coinsin melissas collection

nata0808 [166]

Answer:

X > 40

Step-by-step explanation:

Given that:

Let number of coins in her collection is more Than 40

To represent the number of coins in Melissa's collection as an inequality :

Let total number of items in her collection = X

Coins in her collection > 40

Hence, coins in her collection can be represented as :

X > 40

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3 years ago

Nicole is 56 inches tall and has an 84 inch shadow. Julie is standing next to Nicole and has a 96 inch shadow. How tall is Julie

ki77a [65]

I believe it’s 68 Inches

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3 years ago

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago