All categories

3 years ago

Measure the distance from point A to points B, C, and D. Round to the nearest eighth of an inch. Reduce if possible.

Mathematics

1 answer:

Vlad1618 [11]3 years ago

7 0

Answer:

if its on a coordinate plane the formula would be:

√(2x-1x)²+(2y-1y)²

Step-by-step explanation:

so if the coordinates were

A= (-3,2)

B= (4,2)

C= (4,-1)

D= (-3,-1)

for A to B it would be

√(4 - (-3)² + (2-2)²

√(7)² + (0)²

√(7·7) + (0·0)

√49+0

√49

I hope the explanation helped

You might be interested in

Melissa buys 212 pounds of salmon and 114 pounds of swordfish. She pays a total of $31.25, and the swordfish costs $0.20 per pou

eimsori [14]

Answer:

C. $16.60

Step-by-step explanation:

Let the cost per pound of salmon be represented by x

The cost per pound of swordfish be represented by y

Melissa buys 2 1/2 pounds of salmon and 1 1/4 pounds of swordfish. She pays a total of $31.25

2.5 × x + 1.25× y = $31.25

2.5x + 1.25y = 31.25

The swordfish costs $0.20 per pound less than the salmon.

y = x - 0.20

Hence, we substitute

2.5x + 1.25y = 31.25

2.5y + 1.25(x - 0.20) = 31.25

2.5y + 1.25x - 0.25 = 31.25

2.5x + 1.25x = 31.25 + 0.25

3.75x = 31.5

x = 31.5/3.75

x = $8.4

The cost per pound of salmon be represented by x = $8.4

y = x - 0.20

y = 8.4 - 0.20

y = $8.2

The cost per pound of swordfish be represented by y = $8.2

The cost of a pound of salmon and sword fish

= $8.4 + $8.2

=$16.60

3 0

3 years ago

Pls help with 29 and 19

Phoenix [80]

You should have written like this
1 hour /16 = x hour /100
x=100/16=25/4=6.25
but it asks how many hours after first hour
6.25-1=5.25

5 0

3 years ago

Pls help will mark as brainliest

ASHA 777 [7]

Answer:

Step-by-step explanation:

8 0

3 years ago

The value, V (t), in dollars, of a stock t months after it is purchased is modeled by the following equation.

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation: $V(t)= 42(1-e ^{1.5t} ) +36$ is given value in dollars of a stock in t months after it is purchased.

a) Substitute 1 for t

$V(1) = 42(1-e^{-1.5} )+36 \\=67.852\\=67.85$

V(12) = $V(1) = 42(1-e^{-1.5*12} )+36 \\=77.00$

b) Find derivative for V

$V'(t) = 42(-1.5) e^{-1.5t} )\\\\=-63e^{-1.5t}$

c) When V(t) = 75

$V(t)=75= 42(1-e ^{1.5t} ) +36\\1-e ^{1.5t=0.9286\\=-2.639$

d) As t tends to infinity, exponent being in negative t tends to 0

So V tends to 42(1-0)+36 = 78

3 0

3 years ago

Choose whether it's always, sometimes, never

Keith_Richards [23]

Answer: An integer added to an integer is an integer, this statement is always true. A polynomial subtracted from a polynomial is a polynomial, this statement is always true. A polynomial divided by a polynomial is a polynomial, this statement is sometimes true. A polynomial multiplied by a polynomial is a polynomial, this statement is always true.

Explanation:

The closure property of integer states that the addition, subtraction and multiplication is integers is always an integer.

If $a\in Z\text{ and }b\in Z$ , then a+b\in Z.

Therefore, an integer added to an integer is an integer, this statement is always true.

A polynomial is in the form of,

$p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0$

Where $a_n,a_{n-1},...,a_1,a_0$ are constant coefficient.

When we subtract the two polynomial then the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

If a polynomial divided by a polynomial then it may or may not be a polynomial.

If the degree of numerator polynomial is higher than the degree of denominator polynomial then it may be a polynomial.

For example:

$f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2$

Then $\frac{f(x)}{g(x)}=x^2+5$ , which a polynomial.

If the degree of numerator polynomial is less than the degree of denominator polynomial then it is a rational function.

For example:

$f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2$

Then $\frac{g(x)}{f(x)}=\frac{1}{x^2+5}$ , which a not a polynomial.

Therefore, a polynomial divided by a polynomial is a polynomial, this statement is sometimes true.

As we know a polynomial is in the form of,

$p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0$

Where $a_n,a_{n-1},...,a_1,a_0$ are constant coefficient.

When we multiply the two polynomial, the degree of the resultand function is addition of degree of both polyminals and the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3 0

3 years ago

Read 2 more answers