I NEED A LOT OF HELP PLEASE! I WILL FAIL IF IT DOESNT GET DONE!

Mathematics

1 answer:

Anna35 [415]3 years ago

5 0

In order to solve for this, we need to find the volumes of both the cylinder and cone described.

In order to find the area of the cylinder:
We use the equation V= $\pi r^{2} h$
So, V= $\pi 6^{2}16$
The volume of the cylinder is therefore approximately 1809.56 $m^{3}$

For the cone:
V= $\pi r^{2} \frac{h}{3}$
So, V= $\pi 6^{2} \frac{3}{3}$
Thus, the volume of the cone is 113.1 $m^{3}$

We add these volumes together to derive the solution, which is 1922.66 $m^{3}$

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Need help on quiz plz

malfutka [58]

Answer:

x = 34 degrees

Step-by-step explanation:

Each solid line and triangle add up to 180, so start from the left and slowly do your math.

180 - 112 = 68

180 - 68 - 43 = 69

180 - 69 = 111

180 - 111 - 35 = 34

x and the last angle are the same.

8 0

3 years ago

Solve for a and b in the following circles: B) a а b 82°

Crank

Answer:

A.po ang sagot

Step-by-step explanation:

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3 years ago

Read 2 more answers

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a

Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = $\sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}$

= ${^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}$ + .......+ ${^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}$