Question

I NEED A LOT OF HELP PLEASE! I WILL FAIL IF IT DOESNT GET DONE!

Answer 1

In order to solve for this, we need to find the volumes of both the cylinder and cone described.

In order to find the area of the cylinder:
We use the equation V=$\pi r^{2} h$
So, V=$\pi 6^{2}16$
The volume of the cylinder is therefore approximately 1809.56$m^{3}$

For the cone:
V=$\pi r^{2} \frac{h}{3}$
So, V=$\pi 6^{2} \frac{3}{3}$
Thus, the volume of the cone is 113.1$m^{3}$

We add these volumes together to derive the solution, which is 1922.66$m^{3}$