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12345 [234]
3 years ago
10

Which of the following correctly expresses the number below in scientific

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

E. 6.28 x 10^-6

Step-by-step explanation:

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What is the function written in vertex form?
lys-0071 [83]

Answer:

The answer in the procedure

Step-by-step explanation:

The question does not present the graph, however it can be answered to help the student solve similar problems.

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If the coefficient a is positive then the parabola open up and the vertex is a minimum

If the coefficient a is negative then the parabola open down and the vertex is a maximum

case A) we have

f(x)=3(x+4)^{2}-6

The vertex is the point (-4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case B) we have

f(x)=3(x+4)^{2}-38

The vertex is the point (-4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

case C) we have

f(x)=3(x-4)^{2}-6

The vertex is the point (4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case D) we have

f(x)=3(x-4)^{2}-38

The vertex is the point (4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

4 0
3 years ago
It’s in the picture <br> P.S. the answer isn’t 64
sveta [45]

Answer:

2+6-3+7

8-10

-2

-2+x^4+3+1=

-2+x^8

-2x^8

5 0
2 years ago
Help how can I Write the given standard equation of the quadratic in intercept form
olya-2409 [2.1K]

Answer:

f(x) = (x - 10) (x + 10)

Step-by-step explanation:

The equation looks like the difference of squares so 5 and 20 are out

-10 x -10 = 100

-10 x 10 = - 100

so (x - 10) (x + 10)

7 0
2 years ago
In a sequence described by a function, what does the notation f(3)=1 mean
vladimir2022 [97]
X = 3
Y = 1

f(3)=1
X Y
5 0
3 years ago
Read 2 more answers
Which equation could represent a circle with a center located at (11,-5)
Anon25 [30]
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0
3 years ago
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