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3 years ago

This is line segments

Mathematics

2 answers:

lianna [129]3 years ago

8 0

Step-by-step explanation:

$here \: given \: that \: total \: lenth = bd = 67 \\ then \: bd = bc + cd \\ so \: we \: can \: write \: that \\ 67 = 3x - 2 + 4x + 13 \\67 = 3x + 4x - 2 + 13 \\ 67 = 7x + 11 \\ 7x = 67 - 11 \\ 7x = 56 \\ x = \frac{56}{7} \\ x = 8 \\ thankyou$

arlik [135]3 years ago

6 0

Answer:

$\huge\boxed{\sf 22}$

Step-by-step explanation:

By looking at the line segment, we get to know that:

BD = BC + CD

<u>Given that:</u>

BD = 67

BC = 3x - 2

CD = 4x + 13

<u>Solution:</u>

Put the givens in the above equation made.

67 = 3x - 2 + 4x + 13

67 = 3x + 4x - 2 + 13

67 = 7x + 11

7x = 67 - 11

7x = 56

Divide both sides by 7

x = 56 / 7

x = 8

<u>Now, Finding BC:</u>

= 3x - 2

Put x = 8

= 3(8) - 2

= 24 - 2

= 22

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

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Answer: The required probability is $\dfrac{5}{6}$

Step-by-step explanation:

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Help! Geometry Triangle Congruence

Feliz [49]

Answer:

Step-by-step explanation:

Thank your for revising and improving the image.

Assuming DF is a straight line,

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2 years ago

B) T is due north of C, calculate the bearing of B from C

choli [55]

Answer:

(a) 52°

(b) 322°

Step-by-step explanation:

(a) The details of the circle are;

The diameter of the circle = AOC

The center of the circle = Point O

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The point the tangent PT touches the circle = Point C

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We have that angle AOB and angle COB are supplementary angles, therefore;

∠AOB + ∠COB = 180°

∠AOB = 180° - ∠COB

∴ ∠AOB = 180° - 76° = 104°

∠AOB = 104°

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∠TCA = 90° and ΔTCA = A right triangle

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∴ ∠TCB = 180° - (90° + 52°) = 38°

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