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igor_vitrenko [27]
2 years ago
9

Solve for x. Geometry problem.

Mathematics
1 answer:
barxatty [35]2 years ago
5 0

Answer:

12.33

Step-by-step explanation:

6x - 2 + 9x - 3 = 180° (linear pair)

6x + 9x - 2 - 3 = 180°

15x - 5 = 180°

15x = 180 + 5

15x = 185

x = 185/15

x = 12.33

hope this helps you!

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Explain why parallelograms are always
Mars2501 [29]

Answer: Parallelogram is a kind of quadrilateral where as there are some quadrilaterals (like trapezoid , kite, .. ) that do not satisfy the properties of parallelograms.

Step-by-step explanation:

A quadrilateral is a closed polygon having fours sides.

A parallelogram is a kind of quadrilateral having following properties:

Its opposite sides and opposite angles are equal.

The sum of adjacent angles is 180°.

The diagonal of parallelogram bisect each other.

A Trapezoid is also a quadrilateral . It has only one pair of parallel sides. (The other one are not parallel).

So , all quadrilaterals not parallelograms.

Therefore, parallelograms are always quadrilaterals but quadrilaterals are sometimes parallelograms because parallelogram is a kind of quadrilateral where as there are some quadrilaterals (trapezoid , kite, .. ) ) that do not satisfy  the properties of parallelograms.

plz mark me as brainliest :)

6 0
3 years ago
G/3 + 11 = 25 please help​
pochemuha

Answer: g = 42

Step-by-step explanation:

g/3 + 11 = 25

First, subtract 11 to both sides

g/3 = 14

Then, multiply 3 to both sides to get rid of the fraction

g=42

8 0
3 years ago
19 times 15 with estimating
VladimirAG [237]
284....................
3 0
3 years ago
Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
2 years ago
ASAP Two points ___________ create a line. A. sometimes B. always C. never D. not enough information
Juliette [100K]

Two points NEVER create a line.

3 0
3 years ago
Read 2 more answers
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