Let us add consecutive odd numbers and try to find any relationship.
1. 1
2. 1+3 = 4 ( square of 2 i.e 
)
3. 1+3+5 = 9 ( 
)
4. 1+3+5+7 = 16 (
)
5. 1+3+5+7+9 = 25 (
)
6. 1+3+5+7+9+11 = 36 ( 
)
7. 1+3+5+7+9+11+13 = 49 (
)
If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to . The sum of the numbers in the fifth line is equal to .
Answer:
UV
Step-by-step explanation:
Given:
QSR is a right triangle.
QT = 10
TR = 4
To find:
The value of q.
Solution:
Hypotenuse of QSR = QT + TR
= 10 + 4
= 14
Geometric mean of similar right triangle formula:
Do cross multiplication.
Switch the sides.
Taking square root on both sides.
The value of q is 
.
6x-15=3(4x+3)
Distribute the three to the parentheses
6x-15=12x+9
Transfer the 6 over to the 12 by subtracting it
-15=6x+9
Subtract 9 from 15
-24=6x
Then divide the six by the -24
X=-4
Answer:
first would be 8
second is 12
third is 16
last is 6
Step-by-step explanation:
