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Mars2501 [29]
3 years ago
8

Find the distance between (-3,5) and (-6, -4) please help

Mathematics
1 answer:
Kipish [7]3 years ago
5 0
<h3>The distance between Two co-ordinates =</h3>

\sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2}}

Here,

x1 = - 3

y1 = 5

x2 = - 6

y2 = - 4

Distance =

=  \sqrt{ { ( (- 6 ) - ( - 3))}^{2} +  { ( - 4 - 5)}^{2}  }  \\  =  \sqrt{ {( - 3)}^{2} +  {( - 9)}^{2}  }  \\  =  \sqrt{9 + 81}  \\  =  \sqrt{90}

Hope this will help you....

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Step-by-step explanation:

We have the system of equations:

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Now, first let's define the terms used in the question.

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consistent and dependent: we have infinite solutions.

inconsistent: we do not have solutions.

Now, let's look at the system:

y = 4x - 4

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Let's take the quotient between both the equations:

(y/y) = (4x - 4)/(-4x + 4)

1 = (4x - 4)/(-4x + 4)

let's see if we can solve this for x.

1*(-4x + 4) = 4x - 4

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x = -8/-8 = 1.

and to find the value of y, we can input this value of x in one of the equations:

y = 4*1 - 4 = 0.

Then we have only one solution, (1, 0).

(and will be the same if you input x in the other equation, as the right side is minus the right side of the first equation)

Then the system is consistent and independent.

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Step-by-step explanation:

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