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Dmitriy789 [7]
2 years ago
7

Part A: Solve the following system of authentically showing your work: 3x + 2y = 4 4x + 3y = 7.

Mathematics
1 answer:
IgorC [24]2 years ago
6 0

This is hard.................

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If x -9 is a factor of x^2 -5x-36 , what is the other factor ?
faust18 [17]

Answer:

(x + 4) (x - 9)

Step-by-step explanation:

Factor the following:

x^2 - 5 x - 36

The factors of -36 that sum to -5 are 4 and -9. So, x^2 - 5 x - 36 = (x + 4) (x - 9):

Answer: (x + 4) (x - 9)

3 0
2 years ago
Me.Hatch bought 4 round-trip airplan tickets for $417 each. He also paid $50 in baggage fees. How much did Mr.Hatch spend
Stella [2.4K]

4 * 417 + 50

1668+50

1718

Mr Hatch spent $1718

5 0
2 years ago
Read 2 more answers
Find the midpoint of (0, 4) and (2, -2)
lidiya [134]

Answer:

\text{Midpoint} = (1, \; 1)

Step-by-step explanation:

M = (x_M, \; y_M)

M = \left(\dfrac{x_1 + x_2}{2}, \; \dfrac{y_1 + y_2}{2}\right)

M = \left(\dfrac{0 + 2}{2}, \; \dfrac{4 + -2}{2}\right)

M = \left(\dfrac{2}{2}, \; \dfrac{2}{2}\right)

M = (1, \; 1)

5 0
2 years ago
Read 2 more answers
a fair coin is flipped 10 times. what is the probability of getting the same number of heads and tails
Dafna11 [192]

If you flip a coin one time, the probability to get a Head is

p = 1/2

The probability of not getting a head in a single toss is :

q = 1 - 1/2 = 1/2

Thus there is only one unique situation to get the same number of heads and tails : in 10 toss you need to get exactly five heads, it will means that the rest is the tails.

Now using Binomial theorem of probability, the probability of getting exactly x = 5 heads in a total of n = 10 tosses is :

P(X = 5) = \frac{10!}{5!*5!} *(\frac{1}{2})^{5} *(\frac{1}{2})^{5}≈ 0.246

So the probability of that is 24,6 %

Good Luck

3 0
2 years ago
PLEASE HELP.
Setler79 [48]
Yes you can and you do that by multiplying $42×1.30=54.60 and then $54.60×1.25=68.25
8 0
3 years ago
Read 2 more answers
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