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mars1129 [50]
3 years ago
7

The pH of a softdrink is determined to be 4.0. What is the [OH-] of the drink?

Chemistry
1 answer:
irakobra [83]3 years ago
6 0

Answer: A) 1.0 x 10-10 M

Explanation: The pH is 4.0, and pOH + pH = 14, so pOH = 10. [OH-] = 10^-pOH, so for this drink, [OH-] = 10^-10 M, or 1.0 x 10^-10 M.

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Sue dissolved a certain amount of salt in 400 grams of water to obtain 405 grams of salt solution. What was the mass of the salt
svp [43]
The answer would be 5 grams of salt
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3 years ago
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How many protons do calcium have
Vsevolod [243]
A calcium atom has 20 protons!

There you go! I really hope this helped, if there’s anything just let me know! ☻
6 0
3 years ago
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How many atoms are in 165 g of calcium?
Whitepunk [10]
Atomic mass Calcium = 40.078 a.m.u

40.078 g ---------------- 6.02x10²³ atoms
165 g -------------------- ??

165 x ( 6.02x10²³) / 40.078 => 2.47x10²⁴ atoms

hope this helps!
4 0
3 years ago
For the following electron-transfer reaction:
creativ13 [48]

Answer:

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

Explanation:

Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)

In the oxidation half reaction, the oxidation number increases:

Mn changes from 0, in the ground state to Mn²⁺.

The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.

Silver changes from Ag⁺ to Ag.

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

To balance the hole reaction, we need to multiply by 2, the second half reaction:

Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2

2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)  

Now we sum, and we can cancel the electrons:

2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻

4 0
4 years ago
What is the concentration of magnesium bromide, in ppm, if 133.4 g MgBr2 dissolved in 1.84 L water. Then solve for the bromine c
Serhud [2]

Answer: 0.0725ppm

Explanation:

133.4g of MgBr2 dissolves in 1.84L of water.

Therefore Xg of MgBr2 will dissolve in 1L of water. i.e

Xg of MgBr2 = 133.4/1.84 = 72.5g

The concentration of MgBr2 is 72.5g/L = 0.0725mg/L

Recall,

1mg/L = 1ppm

Therefore, 0.0725mg/L = 0.0725ppm

7 0
3 years ago
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